I think it’s 82 because 78+4=82
GCF= 1
FACTORED VERSION = (X-1) (2X+3)(X+2)
Answer:
The sum of all positive integers less than 100, which are not divisible by 3 is 3267.
Step-by-step explanation:
The all positive integers less than 100 has sum, given by
S₁ = 1 + 2 + 3 + 4 + ......... + 99
⇒ S₁ = 
Now, the sum of all positive integers less than 100 which are divisible by 3 is
S₂ = 3 + 6 + 9 + 12 + 15 + ........ + 99
⇒ S₂ = 3(1 + 2 + 3 + ........ + 33)
⇒ S₂ = 
Therefore, the sum of all positive integers less than 100, which are not divisible by 3 is = S₁ - S₂ = 4950 - 1683 = 3267. (Answer)
Note : The sum of n natural numbers S is given by
S = 1 + 2 + 3 + 4 + ....... + n = 
.
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
