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3 years ago

2 1/3 divied by 2/4 help qwq

Mathematics

2 answers:

Stella [2.4K]3 years ago

6 0

Answer:

4 2/3 OR 14/3

hope this helps!

Greeley [361]3 years ago

6 0

Answer:

4 2/3 or 14/3

Step-by-step explanation:

Applying the fractions formula for division,

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How do I make both these equations into a elimination equation? Look at the pic I’m very confused!

qwelly [4]

Answer:

Step-by-step explanation:

c + a = 342 ..................... (1)

5c + 12a = 2550 ........... (2)

- 5 × (1) + (2)

7a = 840

a = 120

c = 342 - 120 = 222

6 0

2 years ago

What is the solution to 3x² - 2x+4=0

Schach [20]

Answer:

Step-by-step explanation:

2 solutions where found I hope this helps

x =(2-√52)/6=(1-√ 13 )/3= -0.869

x =(2+√52)/6=(1+√ 13 )/3= 1.535

4 0

3 years ago

Find the value of c that makes the expression a perfect square trinomial. x2 + 9 4 x + c

JulijaS [17]

The value of c is 81/64 for the expression a perfect square trinomial.

<h3>What is an Expression?</h3>

An expression can be defined as a mathematical statement that consists of variables, constants and mathematical operators simultaneously.

It is given that an expression

x² +9/4x +c is a perfect square polynomial

c =?

(a+b)² = a² +2ab+b²

2ab = 9/4

b = 9/8

c = b² = 81/64

Therefore the value of c is 81/64 for the expression a perfect square trinomial.

To know more about Expression

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5 0

2 years ago

Help please urgent!

myrzilka [38]

Answer:

Step-by-step explanation:

8 0

3 years ago

We wish to give a 90% confidence interval for the mean value of a normally distributed random variable. We obtain a simple rando

coldgirl [10]

Answer: $(9.27025,\ 11.12975)$

Step-by-step explanation:

Given : Sample size : n= 9

Degree of freedom = df =n-1 =8

Sample mean : $\overline{x}=10.2$

sample standard deviation : $s= 1.5$

Significance level ; $\alpha= 1-0.90=0.10$

Since population standard deviation is not given , so we use t- test.

Using t-distribution table , we have

Critical value = $t_{\alpha/2, df}=t_{0.05 , 8}=1.8595$

Confidence interval for the population mean :

$\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}$

90% confidence interval for the mean value will be :

$10.2\pm (1.8595)\dfrac{1.5}{\sqrt{9}}$

$10.2\pm (1.8595)\dfrac{1.5}{3}$

$10.2\pm (1.8595)(0.5)$

$10.2\pm (0.92975)$

$(10.2-0.92975,\ 10.2+0.92975)$

$(9.27025,\ 11.12975)$

Hence, the 90% confidence interval for the mean value= $(9.27025,\ 11.12975)$

6 0

3 years ago