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nlexa [21]
3 years ago
8

Can you please answer my math question, number two please

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
4 0

Answer:

it equal 420

Step-by-step explanation:

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Kiara spent $36 and had $12 left.<br><br> what percent money did she spend
Illusion [34]

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she spent 75%

Step-by-step explanation:

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Which is the quotient of 396 divided by 12
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To find the quotient, divide 396 by 12.
396/12= 33
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James is 5'10", Emily is 5'7", Ruby is 6'0", Chad is 6'0", Russell is 5'10", and Ariel is 5'9". What is the mean height of those
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34'2" I think

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5 0
3 years ago
URGENT! 100 POINTS TO SOLVE!
masya89 [10]

Answer:

20/5 = x /4 x = 80/5 = 16

x - 10 / 39 = 5/15 = 1/3

3x - 30 = 39

3x = 69

x = 23

(2x + 10 ) * 4 = 10 *(x + 3)

8x + 40 = 10x + 30

2x = 10

x = 4.

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3 0
3 years ago
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Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function f(
alekssr [168]

Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function ()=−(+)^−

<em><u>Answer:</u></em>

vertex = (-4, -5)

Axis of symmetry = -4

use the (-4, -5) to find the minimum value

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

<em><u>Solution:</u></em>

Given function is:

f(x) = (x+4)^2 - 5

The equation in vertex form is given as:

y = a(x-h)^2+k

Where, (h, k) is constant

On comparing give function with vertex form,

h = -4

k = -5

Vertex is (-4 , -5)

Axis of symmetry : x co-ordinate of vertex

Thus, axis of symmetry = -4

The coefficient of x^2 is positive in given function.

Thus the vertex point will be a minimum

Minimum\ value = f(\frac{-b}{a})

f(x) = x^2 + 8x + 16 - 5\\\\f(x) = x^2 + 8x + 11

f(x) = ax^2+bx+c

On comparing,

a = 1

b = 8

x = \frac{-b}{2a} = \frac{-8}{2 \times 1} = -4

f(-4) = (-4)^2 + 8(-4) + 11 = 16 - 32 + 11 = -5

Thus, use the (-4, -5) to find the minimum value

Domain and range

f(x) = (x+4)^2 - 5

The domain is the input values shown on the x-axis

The range is the set of possible output values f(x)

Therefore,

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

4 0
3 years ago
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