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dimaraw [331]
2 years ago
11

An experiment will be conducted in which 20 pepper plants are randomly assigned to two groups. The plants in Group 1 will receiv

e the current fertilizer, Fertilizer A, and the plants in Group 2 will receive a new fertilizer, Fertilizer B. All other growing conditions, including amount of sunlight and water, will be kept the same for the two groups. The growth of the pepper plants will be compared for the two groups. What are the experimental units in this experiment?
A. The two types of fertilizer
B. The sunlight and amount of water
C. The 10 plants in Group 1
D. The 10 plants in Group 2
E. The 20 plants in the two groups
Mathematics
1 answer:
Studentka2010 [4]2 years ago
7 0

The experimental units in this experiment are the 10 plants in group 2.

The experimental unit is a term used in science to refer to an individual or group of objects that are initially equivalent and then undergo experimental processes.

According to the above, the experimental unit of this experiment is the group 2 of plants because these are the plants that are going to be put into experimentation with a new fertilizer.

Then, the answer is D, because it refers to the experimental unit corresponding to this experiment.

Learn more in: brainly.com/question/17034824

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Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
128 is 74% of what number
GarryVolchara [31]
Percent means parts out of 100
74%=74/100=0.74


'of' means multiply


so
128 is 74% of what means
128=0.74 times what
divide both sides by 0.74
172.97297297297297297297297297297=what
the number is about 173

5 0
3 years ago
On two tests so far this year, a student received a 78 and a 93. The student wants an average between 80 and 90 inclusive. What
Mariulka [41]
<span>240 <= 171 + x <= 270
and now subtract 171 from all and get
69 <= x <= 99
So any score from 69 to 99 will do.</span>
8 0
3 years ago
Helpppppppppppppppppppppppppppppppppppppp
Dmitry_Shevchenko [17]
Answer: 403

find the absolute value of -272, which is 272.

add 272 to the 131

that equals the height of 403 ft
4 0
3 years ago
Read 2 more answers
The length of a rectangle is 2cm less than 7 times the width. the perimeter is 60cm. find length
Bezzdna [24]

Answer:

26 cm

Step-by-step explanation:

we can make an equation to find the lengths

2(x+7x-2) = 60

x : length of width

7x-2 : the length of length

2 : the two pairs of length and width

solving this equation, we get x = 4

but that is not the answer

we have to plug in x=4 into 7x-2

7*4-2 = 28-2 = 26

4 0
3 years ago
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