Answer: The answer is C on edg.
Step-by-step explanation: I got it right
Factor out the GCF of
21
b
2
c
2
from
63
b
2
c
4
+
42
b
3
c
2
.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from each term in the polynomial.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from the expression
63
b
2
c
4
.
21
b
2
c
2
(
3
c
2
)
+
42
b
3
c
2
Factor out the GCF of
21
b
2
c
2
from the expression
42
b
3
c
2
.
21
b
2
c
2
(
3
c
2
)
+
21
b
2
c
2
(
2
b
)
Since all the terms share a common factor of
21
b
2
c
2
, it can be factored out of each term.
21
b
2
c
2
(
3
c
2
+
2
b
)
The greatest common factor
GCF
is the term in front of the factored expression.
21
b
2
c
2
Answer:
1999
Step-by-step explanation:
y = 0.2313(y - 1992)^2 + 2.600(y - 1992) + 35.17
verify with known data point
y = 0.2313(2004 - 1992)^2 + 2.600(2004 - 1992) + 35.17
y = 0.2313(12)^2 + 2.600(12) + 35.17
y = 27.9873 + 28.6 + 35.17
y = 99.6772 which verifies our equation
65 = 0.2313x² + 2.6x + 35.17
0 = 0.2313x² + 2.6x - 29.83
quadratic formula
x = (-2.6 ±√(2.6² - 4(0.2313)(-29.83))) / (2(0.2313))
x = (-2.6 + 5.86) / 0.4626 = 7.05 years
7.05 = y - 1992
y = 1999.05
Answer:
30 baskets
Step-by-step explanation:
The experimental probability Pa that Amir will make a basket is 0.4;
Pa = 0.4
the experimental probability Pj that juju with make the same basket is 0.6;
Pj = 0.6
Total number of shoot Nt = 150
Number of basket Amir will make is;
Na = Pa × Nt
Na = 0.4 × 150
Na = 60 basket
Number of basket juju will make is;
Nj = Pj × Nt
Nj = 0.6 × 150
Nj = 90 basket
Answer:
30%
Step-by-step explanation:
