<span><span>You draw a queen on the first draw and one on the second<span><span><span>4/52 </span>∗ <span>3/51 </span>= <span>12/2652 </span>= <span>1/22 </span></span></span></span><span>
You draw something other than a queen on the first draw and a queen on the second<span><span><span>
48/52 </span>∗ <span>4/51 </span>= <span>192/2652</span>=<span>16/221</span></span></span></span></span>
So in total, the chance is:
<span><span><span>1/221 </span>+ <span>16/221 </span>= <span>17/221</span>=
<span>4/52</span></span></span>
Answer:
4.1
Step-by-step explanation:
5^2 + (2*8) / (2*2) + 3*3
25 + 16 / 4 + 6
41 / 10
4.1
It would look like this: x times 7 -> 7x
The first and last table.
As the x increases by 2, the y goes down by 1, so both tables have the same rate of change which means they are the same function.