Question

HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME​

Answer 1

Asked:

• The bigger pizza between the two given pizza.
• The area of the two pizza.

Given:

• First Pizza - radius of 12 inches
• Second Pizza - diameter of 20 inches

PLAN

Operation(s):

• Multiplication

Number Sentence/Formula:

• A¹ = (3.14) (12 in)²
• A² = 1/4 (3.14)(20 in)²

SOLVE

Solution:

• A¹ = πr²
• A¹ = (3.14) (12 in)²
• A¹ = (3.14) (144 in²)
• A¹ = 452.16 in²

• A² = ¼ πd²
• A² ¼ (3.14)(20 in)²
• A² = 3.14/4 (400 in²)
• A² = 3.14 x 100 in²
• A² = 314 in²

LOOK BACK

Answer

• The first pizza is larger than the second pizza.
• The areas of the two pizza are 452.16 square
• inches and 314 square inches, respectively.

$:)$