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3 years ago

B lies along segment AC between

Mathematics

1 answer:

insens350 [35]3 years ago

5 0

Answer:

No, B is not the midpoint of segment AC because segment of AB is 2 cm longer then segment BC

Step-by-step explanation:

See Above Image

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Eduardo has 24$ saved . if he saves 8$ each week how much money will he in 5 weeks .

lyudmila [28]

Answer:

is you are not adding in the 24 then 40 if you are adding in the 24 then 64

Step-by-step explanation:

8 0

3 years ago

Can somebody help me with this question plz !

lidiya [134]

Answer:

y=4x-3

Step-by-step explanation:

Parallel lines will always have the same slope (the number that comes before x in an equation). So, we can plug in 4 to the equation.

y=4x+?

Let's say the ? is b. If we plug in the point (1,1) into y=4x+b, we get

1=4(1)+b

reduce

1=4+b

subtract 4 from both sides

-3=b

and now we can add b=-3 into the original answer, and we get y=4x-3!

5 0

3 years ago

What is the length (magnitude) of the vector (2,-1)?

KiRa [710]

Answer:

$\sqrt{5}$

Step-by-step explanation:

The given vector is represented by (2,-1).

This can be represented in general form as (x,y) where x=2 and y=-1.

Magnitude of the vector represented as (x,y) is given by $[\sqrt{x^{2}+y^{2}}\]$

Evaluating for the given values of x and y,

$\sqrt{2^{2}+(-1)^{2}}$ $=\sqrt{4+1}$

$=\sqrt{5}$

Length of the vector is $\sqrt{5}$

5 0

3 years ago

maria buys 8 1/3 pounds of beef to make tacos for a party .She uses 5/9 pound of beef for each toco. how many tacos can maria ma

Olin [163]

Just do 8 1/3 divided by 5/9 or

25/3 / 5/9

25/3 * 9/5 = 5/1 * 3/1 = 15

So 15 tacos

* = times

/ = divided by

7 0

3 years ago

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks. Two students in t

melomori [17]

Answer:

The system of equation used to find the Total number of flash cards made are $\left \{ {{5x+5} \atop {6x}} \right.$ .

In 5 minutes, each student will have 30 flash cards.

Step-by-step explanation:

Given:

Number of flash cards already made by Tristan = 5

Number of flash card Tristan makes in 1 min = 5

Number of flash card Josh makes in 1 min = 6

We need to find the How long will Josh have same number of flashcards.

Also We need to find how many flashcards will each student have at that point.

Solution:

Let the number of minutes be $'x'$ .

Now we can say that;

Total number of flash cards made by Tristan is equal to Number of flash cards already made by Tristan plus Number of flash card Tristan makes in 1 min multiplied by number of minutes.

framing in equation form we get;

Total number of flash cards made by Tristan = $5+5x$

Also We can say that;

Total number of flash cards made by Josh is equal Number of flash card Josh makes in 1 min multiplied by number of minutes.

framing in equation form we get;

Total number of flash cards made by Josh = $6x$

Hence the system of equation used to find the Total number of flash cards made are $\left \{ {{5x+5} \atop {6x}} \right.$ .

Now to find the number of minutes when both would have same number of flash cards we will make both the equation equal.

so we get;

$5+5x=6x$

On solving we get;

Combining like terms we get;

$6x-5x=5\\\\x=5\ mins$

Hence It would take 5 minutes when both will have same number of flash cards.

To find the number of flash cards each would had at that time we will substitute value of $x=5$ in the system of equations.

so we get;

number of flash cards made by Tristan = $5x+5 = 5\times5+5=25+5=30$

number of flash cards made by Josh = $6x =6\times 5 =30$

Hence In 5 minutes, each student will have 30 flash cards.

6 0

3 years ago