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tiny-mole [99]
3 years ago
8

Item 5

Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0

Answer:

−13.35

Step-by-step explanation:

i took the quiz

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Perform the following operations s and prove closure. Show your work.
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Answer:

1. \frac{x}{x+3}+\frac{x+2}{x+5} = \frac{2x^2+10x+6}{(x+3)(x+5)}\\

2. \frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16} = \frac{1}{(x+2)(x-4)}

3. \frac{2}{x^2-9}-\frac{3x}{x^2-5x+6} = \frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}

4. \frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3} = \frac{1}{(x-2)(x-4)}

Step-by-step explanation:

1. \frac{x}{x+3}+\frac{x+2}{x+5}

Taking LCM of (x+3) and (x+5) which is: (x+3)(x+5)

=\frac{x(x+5)+(x+2)(x+3)}{(x+3)(x+5)}\\=\frac{x^2+5x+(x)(x+3)+2(x+3)}{(x+3)(x+5)} \\=\frac{x^2+5x+x^2+3x+2x+6}{(x+3)(x+5)} \\=\frac{x^2+x^2+5x+3x+2x+6}{(x+3)(x+5)} \\=\frac{2x^2+10x+6}{(x+3)(x+5)}\\

Prove closure: The value of x≠-3 and x≠-5 because if there values are -3 and -5 then the denominator will be zero.

2. \frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16}

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

Factors of x^2+5x+6 = x^2+3x+2x+6 = x(x+3)+2(x+3) =(x+2)(x+3)

Putting factors

=\frac{x+4}{(x+3)(x+2)}*\frac{x+3}{(x-4)(x+4)}\\\\=\frac{1}{(x+2)(x-4)}

Prove closure: The value of x≠-2 and x≠4 because if there values are -2 and 4 then the denominator will be zero.

3. \frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}

Factors of x^2-9 = (x)^2-(3)^2 = (x-3)(x+3)

Factors of x^2-5x+6 = x^2-2x-3x+6 = x(x-2)+3(x-2) =(x-2)(x+3)

Putting factors

\frac{2}{(x+3)(x-3)}-\frac{3x}{(x+3)(x-2)}

Taking LCM of (x-3)(x+3) and (x-2)(x+3) we get (x-3)(x+3)(x-2)

\frac{2(x-2)-3x(x+3)(x-3)}{(x+3)(x-3)(x-2)}

=\frac{2(x-2)-3x(x+3)}{(x+3)(x-3)(x-2)}\\=\frac{2x-4-3x^2-9x}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-9x+2x-4}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}

Prove closure: The value of x≠3 and x≠-3 and x≠2 because if there values are -3,3 and 2 then the denominator will be zero.

4. \frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3}

Factors of x^2-5x+6 = x^2-3x-2x+6 = x(x-3)-2(x-3) = (x-2)(x-3)

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

\frac{x+4}{(x-2)(x+3)}\div\frac{(x-4)(x+4)}{x+3}

Converting ÷ sign into multiplication we will take reciprocal of the second term

=\frac{x+4}{(x-2)(x+3)}*\frac{x+3}{(x-4)(x+4)}\\=\frac{1}{(x-2)(x-4)}

Prove Closure: The value of x≠2 and x≠4 because if there values are 2 and 4 then the denominator will be zero.

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The sides of a triangle are 15 units, 25 units, and 20 units. What kind of triangle is this
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Answer:

Right Triangle

Step-by-step explanation:

15² + 20² = 225 + 400 = 625 = 25²

8 0
4 years ago
On April 1, the price of gas at Bob's Corner Station was $3.35 per gallon. On May 1, the price was $3.85 per gallon. On June 1,
Zina [86]
<h2>Answer:</h2>

1. Between April 1 and May 1, Bob's price incrdased by <u>$0.50 or 15%</u>.

2. Between May 1 and June 1, Bob's price decreased by <u>$0.50 or 13%</u>.

3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is <u>$0.1 more expensive</u> when gas costs $3.85 than when gas costs $3.35.

4. Suppose the Fed raises the target for the federal fundsb rate from 2% to 2.25%. This change of percentage points means that the Fed raised its target by approximately <u>0.25%</u>.

<h2>Step-by-step explanation:</h2>

<h3>1. Between April 1 and May 1, Bob's price incrdased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

C= |Original value - New value|/ Original value

C=\frac{|OV-NV|}{OV}=\frac{|3.35-3.85|}{3.35}  =0.15=15%.

<h3>2. Between May 1 and June 1, Bob's price decreased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

C= |Original value - New value|/ Original value

C=\frac{|OV-NV|}{OV}=\frac{|3.35-3.85|}{3.85}  =0.13=13%.

<h3>3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is (blank) when gas costs $3.85 than when gas costs $3.35.</h3>

<em>In this question we are looking for the difference of a difference. </em>

<em>If the proces across the street are always 20% higher, to find how much the gallon costs just multiply the price by 1.20, to increase 0.2 or 20%:</em>

$3.85 * 1.20= $4.62.

<em>Now, to see how much expensive this price is compared to Bob's, take de difference between the prices:</em>

$4.62 - $3.85= $0.77.

<em>Do the same to find the difference between the gas prices when the price is $3.35.</em>

$3.35 * 1.20= $4.02.

$4.02 - $3.35= $0.67.

Now, find the difference of those differences:

$0.77 - $0.67= $0.1.

<h3>4. Suppose the Fed raises the target for the federal funds rate from 2% to 2.25%. This change of percentage points means that the Fed raised its target by approximately (blank).</h3>

<em>Find the difference between percentages:</em>

2.25% - 2%= 0.0225 - 0.02= 0.0025= 0.25%.

<em>Simpler method:</em>

2.25% - 2%= 0.25%.

3 0
2 years ago
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