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3 years ago

I NEED HELP PLEASE!!!

Mathematics

1 answer:

netineya [11]3 years ago

3 0

Answer:

Step-by-step explanation:

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There goes my hopes for Virtuoso rank....

Tpy6a [65]

Y = x^2 + 10x - 171
y = (x - 9)(x + 19)

x - 9= 0 x + 19 = 0
x = 9 x = -19

Answer B covers all requirements... the factored form is
y= (x + 19)(x - 9)
and the zeros are -19 and 9

3 0

3 years ago

If you could help I would really appreciate it, but if not that’s fine. Thank you.

Gre4nikov [31]

Since -1 is less than or equal to -1 you input it into the first equation.

-3•(-1) -4
3-4
-1

the answer is -1 good luck

7 0

3 years ago

In calculating the monthly payment for a five-year loan, what value should be used for n, the number of periods over which the l

Ymorist [56]

The value should be used for n, the number of periods over which the loan is repaid in 60 periods.

We have to determine

In calculating the monthly payment for a five-year loan, what value should be used for n, the number of periods over which the loan is repaid, as it appears in the following formula?

<h3>What formula is used to calculate the monthly payment?</h3>

The value of the monthly payment is given by;

$\rm P=PV\times \dfrac{i}{1-(1+i)^{-n}}$

Where,

PV is the present value or the amount of the loan.

i is the interest rate per period and is calculated by dividing the yearly percent rate by 100 and by the number of periods in a year.

n is the total number of periods and is calculated as the product of the number of periods in a year times the number of years.

Therefore,

The value should be used for n, the number of periods over which the loan is repaid;

n = 6 years × 12 months/year = 60 months = 60 periods.

Hence, The value should be used for n, the number of periods over which the loan is repaid in 60 periods.

To know more about Monthly payment click the link given below.

brainly.com/question/26351994

7 0

3 years ago

The linear question y=-2x+4 is represented on the graph below

shutvik [7]

Answer is (0,4) because 4 is the y-intercept

3 0

4 years ago

How yo simplify (b2/3 x b5/3 x t1/5 x t3/4)?

lesantik [10]

$\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\$

$\bf b^{\frac{2}{3}}\cdot b^{\frac{5}{3}}\cdot t^{\frac{1}{5}}\cdot t^{\frac{3}{5}}\implies b^{\frac{2}{3}+\frac{5}{3}}\cdot t^{\frac{1}{5}+\frac{3}{5}}\implies b^{\frac{7}{3}}t^{\frac{4}{5}}\implies \sqrt[3]{b^7}\cdot \sqrt[5]{t^4}
\\\\\\
\sqrt[3]{b^{1+3+3}}\cdot \sqrt[5]{t^4}\implies \sqrt[3]{b^1b^3b^3}\cdot \sqrt[5]{t^4}\implies bb\sqrt[3]{b}\cdot \sqrt[5]{t^4}\implies b^2\sqrt[3]{b}\cdot \sqrt[5]{t^4}$

4 0

4 years ago