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Lynna [10]
3 years ago
14

Just some points for today

Mathematics
2 answers:
Sidana [21]3 years ago
6 0

Answer:

an unspecified time in the future. later. someday. sooner or later.

anygoal [31]3 years ago
4 0

Answer:

thnx for points hmm nd have a nice day ahead

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Solve for x. Please help
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Answer:

x=11

Step-by-step explanation:

3x+3(5x-6)= 180

Distribute 3 to 5x and -6

3x+15x-18=180

Combine like terms

18x-18=180

Add 18 to both side

18x=198

Divide 18 on both side

x=11

5 0
1 year ago
In Priya's math class there are 10 boys and 15 girls.what is the ratio of boys to girls in Priya's math class?Express your answe
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The ratio is 10/15.

10/15 = 2/3

2/3 = 0.6666...

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3 years ago
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3) You order two pizzas for you and your friends. The total comes to $24.50. The
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27.32 you divide 24.50 and 11.5. Then add what you get from that to 24.50
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What are the x- and y-coordinates of point C, which partitions the directed line segment from A to B into the ratio 5:8? Round t
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Answer: D) (1.2,-4.7)

Step-by-step explanation:

plug in the end corrdinates like it says in the equation that the problem gives you.

7 0
3 years ago
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A random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used. A survey of 500 randomly selecte
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Answer:

We conclude that the mean Ohio score is below the national average.

Step-by-step explanation:

We are given that a random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used.

A survey of 500 randomly selected Ohio scores showed a mean of 20.8. The population standard deviation is 3.

<u><em>Let </em></u>\mu<u><em> = mean Ohio scores.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 21.1      {means that the mean Ohio score is above or equal the national average}

Alternate Hypothesis, H_A : \mu < 21.1      {means that the mean Ohio score is below the national average}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}  ~ N(0,1)

where, \bar X = sample mean Ohio score = 20.8

            \sigma = population standard deviation = 3

            n = sample of Ohio = 500

So, <u><em>test statistics</em></u>  =  \frac{20.8-21.1}{\frac{3}{\sqrt{500}}}  

                              =  -2.24

The value of z test statistics is -2.24.

<em>Now, at 0.1 significance level the z table gives critical value of -1.2816 for left-tailed test.</em><em> Since our test statistics is less than the critical values of z as -2.24 < 1.2816, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the mean Ohio score is below the national average.

4 0
4 years ago
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