Answer:
Maximum is the most allowed or the most your able to put on whatever requires Maximum of anything. Minimum is the Least allowed or the least your able to pu on whatever that requires minimum of anything
Step-by-step explanation:
C because it would be -x so x would be on the other side of 0 on the number line. Then you would add 3 so you would go 3 spaces to the right giving you point C
Answer:
2x-1 is an equivalent answer.
Answer:
D) 9
Step-by-step explanation:
Using proportions, we have
12/2 = 54/x
Cross multiplying, we have
12(x) = 2(54)
12x = 108
Divide both sides by 12:
12x/12 = 108/12
x = 9

Euclid's division lemma : Let a and b are two positive integers. There exist unique integers q and r such that
a = bq + r, 0
r < b
Or We can write it as,
Dividend = Divisor × Quotient + Remainder
<u>Work</u><u> </u><u>out</u><u>:</u>
Given integers are 240 and 228. Clearly 240 > 228. Applying Euclid's division lemma to 240 and 228,
⇛ 240 = 228 × 1 + 12
Since, the remainder 12 ≠ 0. So, we apply the division dilemma to the division 228 and remainder 12,
⇛ 228 = 12 × 19 + 0
The remainder at this stage is 0. So, the divider at this stage or the remainder at the previous age i.e 12

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