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2 years ago

Please help me solve this problem... I will mark you brainliest

Mathematics

1 answer:

DaniilM [7]2 years ago

8 0

Answer:

As the wheel makes this 270 degree counterclockwise rotation about the origin, the y-coordinate of the first car decreases from 80 to 0 and then further from 0 to -80, and finally increases to 0.

The x-coordinate decreases from 0 to -80 and then increases to 0; from there it increases further to 80.

Thus, the coordinates of the first car, after this 270-degree rotation, are (80, 0).

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Help pleasseeeee ! 15 points the answers are (-1,-5) (0,-3) (4,5) (9,15)

svet-max [94.6K]

Answer:

(0,-3)

Step-by-step explanation:

2x-y = 3

x+2y = -6

Multiply the first equation by 2 so we can eliminate y

2(2x-y =3)

4x -2y = 6

Add this to the second equation

4x -2y = 6

x+2y = -6

-----------------

5x +0y = 0

x = 0

Now find t

x+2y = -6

0+2y = -6

2y =-6

Divide by 2

y = -3

5 0

2 years ago

Read 2 more answers

Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.

vesna_86 [32]

Factorize the denominator:

$\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}$

If $x\neq\pm2$ , we can cancel the factors of $x^2-4$ , which makes $x=-2$ and $x=2$ removable discontinuities that appear as holes in the plot of $g(x)$ .

We're then left with

$\dfrac1{x+1}$

which is undefined when $x=-1$ , so this is the site of a vertical asymptote.

As $x$ gets arbitrarily large in magnitude, we find

$\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0$

since the degree of the denominator (3) is greater than the degree of the numerator (2). So $y=0$ is a horizontal asymptote.

Intercepts occur where $g(x)=0$ ( $x$ -intercepts) and the value of $g(x)$ when $x=0$ ( $y$ -intercept). There are no $x$ -intercepts because $\dfrac1{x+1}$ is never 0. On the other hand,

$g(0)=\dfrac{0-4}{0+0-0-4}=1$

so there is one $y$ -intercept at (0, 1).

The domain of $g(x)$ is the set of values that $x$ can take on for which $g(x)$ exists. We've already shown that $x$ can't be -2, 2, or -1, so the domain is the set

$\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}$

8 0

2 years ago

On a number line, the coordinates of A, B, C, and Dare -6, -2, 3, and 7, respectively. Find

den301095 [7]

Answer:

9: not congruent AB=-8 and CD=10

10: not congruent AC=-3 and BD=5

11: congruent BC=1 and AD=1

5 0

2 years ago

Tell if I was right, and I'll thank you and mark you as branliest

PtichkaEL [24]

It is my opinion that it is C) but i am not sure, you might be correct though...

8 0

2 years ago

The fifth graders were given sandwiches for lunch during your field trip Nathan ate 5 out of 6 leroy ate 7 out of 8 of his sandw

Scorpion4ik [409]

Answer:

Step-by-step explanation:

The fifth graders were given sandwiches for lunch during their field trip. Nathan ate 5/6 of his sandwich, Leroy ate 7/8 of his sandwich, and Sofia ate 5/8 of her sandwich. Who ate the greatest amount of their sandwich? ... Nathan ate 20/24, Leroy ate 21/24, and Sofia ate 15/24 meaning Leroy ate the most.

5 0

3 years ago

Read 2 more answers