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larisa86 [58]
3 years ago
9

Can someone please help me.

Mathematics
1 answer:
Art [367]3 years ago
4 0

I will give you everything I can do:

11)

Lets say Car A travels at x mph. That means Car B travels at x+2 mph.

Both of them are traveling towards each others, so we can say the total speed is 2x+2.

Now i takes 3 hrs and we know the distance.

Since R*T=D

Then 3(2x+2)=270

So 2x+2=90

2x=88

x=44

12)

To find perpendicular we want to find the opposite reciprocal of the original slope. Therefore the slope is 3/2.

Now we must find the equation of the line with the given variable.

First find b.

5=3/2*4+b

b = -1

So the equation of this line is:

y=3/2x-1

13) All work will be shown below.

6-3(-2-4x)=2(3(x-4)+7)

6+6+12x=2(3x-12+7)

12+12x=2(3x-5)

12+12x=6x-10

6x=-2

x = -1/3

14)

First we must find the amount each train traveled.

The speed of F train(Freight train)=x

The speed of P train(passenger train)=x+6

Their combined speed is 2x+6

It takes 2 hrs to cover 100 miles

So 2(2x+6)=100

2x+6=50

2x=44

x=22

So the freight train covered 44 miles and the passenger train covered 56 miles.

To find average speed you must do Total Distance/Total Time.

44/2 and 56/2

Which are 22 and 28.

The average speed of F train is 22 mph and average speed of P train is 28 mph.

15) Again opposite reciprocal.

3/5 -> -5/3

Work:

-4=-3*-5/3+b

-4=5+b

b=-9

y = -5/3x-9

16)

F=kx-kx0

First kx0 = 0

So F=kx

So x=F/k

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The distance between the anchor points of the two guy wires holding radio antenna is 181 feet (to the nearest foot)

<h3>How to determine the distance between the two anchor points of the guy wire</h3>

The problem will be solved using SOH CAH TOA

let the distance between the 150 ft long guy wire and the radio antenna be x

let the distance between the 180 ft long guy wire and the radio antenna be y

cos 65° = x / 150

x = cos 65° * 150

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The height of the antenna

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height of antenna = 135.95

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Learn more on Pythagoras theorem here:

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<h3>Answer:</h3>

63.64%

<h3>Step-by-step explanation:</h3>

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<em>Comment on fractions involving 11</em>

1/11 is the 2-digit repeating decimal 0.09090909...

So, any multiple of 1/11 is a 2-digit repeating decimal with the two digits being the numerator times 9.

Here, we have 7/11, so the 2-digit repeat is 7·9 = 63. That is ...

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