Answer:
Local minimum at x = 0.
Step-by-step explanation:
Local minimums occur when g'(x) = 0 and g"(x) > 0.
Local maximums occur when g'(x) = 0 and g"(x) < 0.
Set g'(x) equal to 0 and solve:
0 = 2x (x − 1)² (x + 1)²
x = 0, 1, or -1
Evaluate g"(x) at each point:
g"(0) = 2
g"(1) = 0
g"(-1) = 0
There is a local minimum at x = 0.
Short answer: No! <<=====
If the two are one after another, then they are not supplementary, which a parallelogram requires.
If they are in opposite corners, they must be equal. That's another property of parallelograms.
Answer:
the area would be 0.4 or 40%
Step-by-step explanation:
The computation of the area is given below:
But before that the level of the density is
The density level is
= 1 ÷ (3 - 0)
= 1 ÷ 3
Area from 0 miles to 1.2 miles
= (1 ÷ 3) × (1.2 - 0)
= 0.4 or 40 %
Hence, the area would be 0.4 or 40%
the same is considered and relevant too
Answer is<em> </em><em><u>3t²-6t</u></em>
<h3>
Step-by-step Explanation:-</h3>
Now we need to find velocity. The velocity is the first derivative of position, so let's find the derivative of s(t) :-
So,
Therefore, <u>v(t) = 3t²-6t</u>
Answer:
y = 2x - 4
Step-by-step explanation:
We'll write our equation in y = mx + b form, with m being the slope and b being the y-intercept. We already know our slope, so we can replace m with 2 like this: y = 2x + b. But we don't know what b is. We can use the point (3, 2) to figure out b's value, since it has an x-value (3) and a y-value (2):
2 = 2(3) + b
2 = 6 + b
-4 = b
So we have y = 2x + (-4), or y = 2x - 4.
Hopefully that was helpful! If you have more questions, let me know.
