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3 years ago

5

ASAP help due rn and thankyou

2 answers:

tekilochka [14]3 years ago

7 0

Maybe A or C uhm I’m sure it is one of them just dunno which

Brilliant_brown [7]3 years ago

3 0

The answer is; Aaaaaaaaaaa

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Is there any scientific evidence to support the claim that gender is a spectrum? I am writing an article on people who claim to

Oksana_A [137]

I found some articles on the internet that may be helpful (took me three minutes of searching). Hope these help?

http://www.huffingtonpost.com/ravishly/neuroscience-proves-what-_b_6494820.html

http://sitn.hms.harvard.edu/flash/2016/gender-lines-science-transgender-identity/

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3 years ago

In what 2 simple ways can we restore the land?

My name is Ann [436]

Answer:

Land restoration can include the process of cleaning up and rehabilitating a site that has sustained environmental degradation, such as those by natural cause (desertification) and those caused by human activity (strip mining), to restore that area back to its natural state as a wildlife home and balanced habitat.

Explanation:

setting up reliable water provisioning (e.g. by digging wells or placing long-distance water pipes)
stabilizing and fixating the soil

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3 years ago

How does wolf population affect moose population

Luda [366]

The wolf population are the predators

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4 years ago

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An autosomal recessive disease has an incidence of 1/10,000. What is the approximate frequency of heterozygote carriers for this

goblinko [34]

Answer:

Option B

Explanation:

Given

Number of incidences or frequency of an autosomal recessive disease $= \frac{1}{10000}$

As per Hardy Weinberg's equation, frequency of a recessive genotype is $q^{2}$

$q = \sqrt{\frac{1}{10000} }\\ q = \frac{1}{100}$

As per first equation of Hardy Weinberg's -

$p+q=1$

so ,

$p = 1-q\\p = 1-\frac{1}{100}\\p = \frac{99}{100}$

$p^2 = (\frac{99}{100})^2\\p^2 =\frac{9801}{1000}$

As per second equation of Hardy Weinberg's -

$p^{2} + q^{2} + 2pq=1$

Substituting the given values in above equation, we get -

$\frac{9801}{10000} + \frac{1}{100} + 2pq=1\\2pq = 1-(\frac{9801}{10000} + \frac{1}{100})\\2pq = 0.99%\\OR[tex]2pq=1$ %

$2pq = \frac{1}{100}$

Hence, option B is correct.

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3 years ago

The pattern of spacing between individuals across the range of a population is its

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Ja ka hauj hafubj uaiia gqinaf jayijwbh hahaha

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3 years ago