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4 years ago

Help Me Find The Surface Area and look for the expression to round or closest to or exactly the same.

Mathematics

1 answer:

sveticcg [70]4 years ago

3 0

D! Because 2x4=8 and you would have to do that twice and then 1/2x4x6=12 and you would do that twice and 6x2=12

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I need help with my homework

Nimfa-mama [501]

The shaded squares are positive because a negative number multiplied or divided by a negative number makes the product or quotient positive. There is no specific rule that comes to mind, but if your teacher has provided a list of specific rules I would look for something mentioning negative numbers.

6 0

3 years ago

What are the coordinates of point C on the directed segment from A (-8,4) to B (10,2) that partitions the segment such that AC:C

Burka [1]

Answer:

(14/3, 8/3)

Step-by-step explanation:

Let the points be

$(x_1,y_1) = A(-8,4)\\(x_2,y_2) = B(10,2)\\$

The formula for finding the coordinates of point that divides the line in a:b is:

$x = \frac{bx_1+ax_2}{a+b} \\y = \frac{by_1+ay_2}{a+b}$

Here x and y are the coordinates of the point that will partition the line into given ratios

Our ratio is 2 to 1,

So,

a=2

b=1

Putting the values in the formula

$x = \frac{(1)(-8)+(2)(10)}{2+1}\\x = \frac{-8+20}{3}\\x =\frac{14}{3}\\y = \frac{(1)(4)+(2)(2)}{3}\\y=\frac{4+4}{3} \\y= \frac{8}{3}$

So the coordinates of point that divides AB in 2:1 are:

(14/3, 8/3) ..

7 0

4 years ago

Read 2 more answers

The function f(x) = 582(7)x represents the growth of a mosquito population every year in a remote swamp. Troy wants to manipulat

Vladimir79 [104]

Answer: The required function is,

$f(x)=582(7^\frac{1}{6})^{6x}$

Step-by-step explanation:

Since, the population which is increasing with the constant factor is,

$P(x)=ab^x$

Where, a is the initial population,

b is the growth factor per period,

x is the number of periods.

Here, the given function that represents the mosquito population after x years,

$f(x)=582(7)^x$

Where, 7 is the growth factor per year,

Since, 12 months = 1 year,

2 month = 1/6 year.

Also, we can write,

$582(7)^x=582(7)^{\frac{1}{6}\times 6x}=582(7^\frac{1}{6})^{6x}$

$\implies f(x)=582(7^\frac{1}{6})^{6x}$

Which is the required equivalent function that shows the population of mosquito is increasing in every 2 month by the growth factor $7^\frac{1}{6}$ .