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IRINA_888 [86]
3 years ago
8

If x = 3 and y = 6, evaluate the following expression: 100 – 3(3y - 4x)

Mathematics
2 answers:
Ronch [10]3 years ago
7 0
Step by step
1). 3 x y = 18
2). 4 x x = 12
3). 18-12 = 6
4). 6 x 3 = 18
5). 100-18 = 82
Verdich [7]3 years ago
5 0

Answer:

100 – 3(3(6) - 4(3)) = 82

Step-by-step explanation:

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a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-
Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

5 0
3 years ago
The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula

The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

3d = 15

d = 5

If a + 8d = 50 then substitute the value of d = 5, we get

a + 8 * 5 = 50

a + 40 = 50

a = 50 - 40

a = 10.

Therefore, the first term is 10 and the common difference is 2.

To learn more about common differences refer to:

brainly.com/question/1486233

#SPJ4

4 0
2 years ago
What is 12765x6748+6789
slava [35]
Every calculation with multiple operations must abide to BODMAS (Brackets, Other, Divide, Multiple, Addition, Subtraction)

Thus we would multiple first, giving us 86138220. Then we would add giving us: 86145009
3 0
3 years ago
Read 2 more answers
Ari’s teacher says he may have his report grade based on either the mean or the median of his last six test scores.
viva [34]

The mean would be the best! The mean is when you add up all of those grades and divide by the amount of exams.

If you're solving it,

504 is the total divided by 6 tests would be 84.

3 0
3 years ago
Read 2 more answers
4x^-y^2 what and how would you solve this particular problem
dimulka [17.4K]
It is x^4 - y^2  

so, expanding it, (x^2-y)(x^2+y)
 
hope it served
5 0
3 years ago
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