Answer:
3) (I) Numeric , and (II) Numeric
Step-by-step explanation:
Numeric variable:
The variable assume number values.
Categorical values:
The variable assumes labels. Examples are yes/no, good/bad.
(I) Fuel economy (miles per gallon) of used car
(II) Number of auto insurance claims in a month
Both of these variables are numbers, none have labels, so they are both numeric. The correct answer is given by option 3).
When two lines cross, there are four angles at the place where they cross.
Two angles that do NOT share a side are vertical angles. There are two pairs
of vertical angles where the lines cross.
Also, by the way, vertical angles are always equal to each other. It's often
very helpful to know that.
If you would like to know how many free throws did a basketball player attempted, you can calculate this using the following steps:
75% of x is 84
75% * x = 84
75/100 * x = 84
x = 84 * 100 / 75
x = 112 free throws
The correct result would be 1<span>12 free throws.</span>
Answer:
We are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%
Step-by-step explanation:
-From the given information, 
.
-We calculate the confidence interval using this value at 95% confidence level:
![CI=\hat p\pm z \sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\\\=0.65\pm 1.96\times \sqrt{\frac{0.65\times 0.35}{12000}}\\\\\\=0.65\pm 0.0085\\\\\\=[0.6415,0.6585]](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z%20%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%5C%5C%5C%5C%5C%5C%3D0.65%5Cpm%201.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.65%5Ctimes%200.35%7D%7B12000%7D%7D%5C%5C%5C%5C%5C%5C%3D0.65%5Cpm%200.0085%5C%5C%5C%5C%5C%5C%3D%5B0.6415%2C0.6585%5D)
So, the 95% confidence interval is (0.6515,0.6585).
Hence, we are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%.
