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3 years ago

Please help i don't understand

Mathematics

1 answer:

alexira [117]3 years ago

3 0

Answer:

Step-by-step explanation:

The diagonals of a parallelogram bisect each other. Hence, the two shorter sides created on diagonal RT ("6x-7" and "x+28" ) are equal.

We can set them equal and solve for x:

$6x-7=x+28\\6x-x=28+7\\5x=35\\x=\frac{35}{5}\\x=7$

So the side length of 6x -7 is:

6(7)-7 = 35

and the side length of x + 28 is:

7 + 28 = 35

THus, the diagonal RT = 35 + 35 = 70 units

Answer choice A is right.

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A. E ( U ) = 21.5454 , E ( F ) = 8.39333

B. M ( U ) = 17.0 , M ( F ) = 18.0

C. E ( U' ) = 17.0 , E ( F' ) = 7.95384

D. T ( U ) = 9.091% , T ( F ) = 6.667%

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Solution:-

- Two sample sets ( U ) and ( F ) that define the concentration ( EU/mg ) of endotoxin found in urban and farm homes as follows:

U: 6.0 5.0 11.0 33.0 4.0 5.0 80.0 18.0 35.0 17.0 23.0

F: 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 22.0 9.6 2.0 2.0 0.5

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Xi : Data iteration

n: Sample size

Therefore,

$E ( U ) = \frac{Sum (U_i )}{n_u} \\\\E ( U ) = \frac{6.0 + 5.0 + 11.0 + 33.0 + 4.0+ 5.0 +80.0+ 18.0+ 35.0+ 17.0+ 23.0 }{11} \\\\E ( U ) = 21.54545\\\\E ( F ) = \frac{Sum (F_i )}{n_f} \\\\E ( F ) = \frac{2.0 + 15.0 + 12.0 + 8.0 + 8.0 + 7.0 + 6.0 + 19.0+ 3.0+ 9.8+ 22.0+ 9.6+ 2.0+ 2.0+ 0.5 }{15} \\\\E ( F ) = 8.39333$

- To determine the sample median we need to arrange the data for both samples ( U ) and ( F ) in ascending order as follows:

U: 4.0 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0 80.0

F: 0.5 2.0 2.0 2.0 3.0 6.0 7.0 8.0 8.0 9.6 9.8 12.0 15.0 19.0 22.0

- Now find the mid value for both sets:

Median term ( U ) = ( n + 1 ) / 2

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Median ( U ), 6th term = 17.0

Median term ( F ) = ( n + 1 ) / 2

= ( 15 + 1 ) / 2 = 16/2 = 8th term

Median ( F ), 8th term = 8.0

- We will now trim the smallest and largest observation from each set.

- In set ( U ) we see that smallest data corresponds to ( 4.0 ) while the largest data corresponds to ( 80.0 ). We will exclude these two terms and the trimmed set is defined as:

U': 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0

- In set ( F ) we see that the smallest data corresponds to ( 0.5 ) while the largest data corresponds to ( 22.0 ). We will exclude these two terms and the trimmed set is defined as:

F': 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 9.6 2.0 2.0

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$E ( U' ) = \frac{5.0+ 5.0+ 6.0+ 11.0+ 17.0+ 18.0+ 23.0+ 33.0+ 35.0}{9} \\\\E ( U' ) = 17$

$E ( F' ) = \frac{2.0 +2.0+ 2.0 +3.0+ 6.0+ 7.0+ 8.0+ 8.0+ 9.6+ 9.8+ 12.0+ 15.0+ 19.0}{13} \\\\E ( F' ) = 7.95384$

- The trimming percentage is known as the amount of data removed from the original sample from top and bottom of sample size of 11 and 15, respectively.

- We removed the smallest and largest value from each set. Hence, a single value was removed from both top and bottom of each data set. We can express the trimming percentage for each set as follows:

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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

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