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RSB [31]
2 years ago
13

1.What must be used to tell if a collection of items is a set?

Mathematics
1 answer:
Mnenie [13.5K]2 years ago
3 0
1. A set is described either by listing all its elements between braces { } (the listing method), or by enclosing a rule within braces that determines the elements of the set (the rule method).
Example: So if P(x) is a statement about x, then S = { x | P ( x )} means “S is the set of all x such that P(x) is true.”

2. Types of set:
• Empty, or null, set {∅}.
• finite sets
• infinite set.

3. An infinite set: The set whose elements cannot be listed, i.e., set containing never-ending elements. Example: Set of all points in a plane.

4. The union of two given sets is the smallest set which contains all the elements of both the sets. To find the union of two given sets A and B is a set which consists of all the elements of A and all the elements of B such that no element is repeated. The symbol for denoting union of sets is ‘∪’.

The union of sets A and B, denoted by A ∪ B, is the set of elements formed by combining all the elements of A and all the elements of B into one set.
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What is the logarithmic form of the equation e3x ≈ 3247?
lesya [120]
E^(3x) = 3247

3x = log 3247

x = [log 3247]/3
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3 years ago
Help help help ASAP math math
Lorico [155]
29 mg = 0.029 g hope this helps
4 0
2 years ago
Read 2 more answers
Show 3.5, 0 0n quadrant plane
Fiesta28 [93]

Answer:

Right 3.5 units

Step-by-step explanation:

Well, the coordinates go (x,y) so just plug it in..

(3.5, 0)

Go across (to the right) 3.5 and up 0, that's it.

Hope this helps :)

8 0
2 years ago
Which does not describe the same situation y=3x+5
Naddika [18.5K]
Given the function. y = 3x + 5

For, x = -3; y = 3(-3) + 5 = -9 + 5 = -4
For x = 1; y = 3(1) + 5 = 3 + 5 = 8
For x = 4; y = 3(4) + 5 = 12 + 5 = 17

Thus the table representing the function is the table with: -3, 1 and 4 as x-values and -4, 8, 17 as y-values.

For x = 0; y = 3(0) + 5 = 0 + 5 = 5
For y = 0; 0 = 3x + 5; 3x = -5 and x = -5/3

Thus the graph of the function is a straight line passing through points (0, 5) and (-5/3, 0).

To illustrate the fuction as a word statement we say that y is five more than three times x


From the given descriptions, the graph does not represent the graph of y = 3x + 5.

Therefore, the one that does not describe the same situation is the graph.
3 0
3 years ago
For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr
pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables X_i with the following distribution:

X_i Bin (1,p) = Be(p) bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:

Z = \sum_{i=1}^N X_i

From the info given we know that N \sim Bin (M,q)

We need to proof that Z \sim Bin (M, pq) by the definition of binomial random variable then we need to show that:

E(Z) = Mpq

Var (Z) = Mpq(1-pq)

The deduction is based on the definition of independent random variables, we can do this:

E(Z) = E(N) E(X) = Mq (p)= Mpq

And for the variance of Z we can do this:

Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2

Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2

And if we take common factor Mpq we got:

Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]

And as we can see then we can conclude that   Z \sim Bin (M, pq)

8 0
3 years ago
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