Answer:
d = 2
the diagonals are the different lengths
Step-by-step explanation:
Answer:

Step-by-step explanation:
Part I
The problem can be expressed as follows;
The dividend is 4·x⁴ - 5·x³ + 2·x² - x + 5
The divisor is x² + x + 1

Part II
The number of times x² goes into the larest term, 4·x⁴ = 4·x² times
2·x² - 9·x + 7

<u>4·x⁴ + 4·x³ + 4·x²</u>
-9·x³ - 2·x² - x + 5
<u>-9·x³ - 9·x² - 9·x</u>
7·x² + 8·x + 5
<u>7·x² + 7·x + 7</u>
x - 2
Therefore, we have;

Answer:
A)equation=A=318-27.9·T
b)A=318-27.9·6= A=150.6 students per counselor
C)200=318-27.9·T= 4.2 Years
Step-by-step explanation:
A) A=318 students per guidance counselor, that number decreases
T= time that passed from 2009
Then the equation would be like==
A(students per counselour)= 318(Number in 2009)-27.9(Less every year)·T
b)Resolve thje equation changing T by 6---->Thats because 2015-2009=6
A=318-27.9·6= 150.6 students per counselor.
C) Resolve the equation changing A by 200
200=318-27.9·T= (200-318)÷(-27.9)== 4.2 years(T)