Question

Whats the positive and negative points of f(x)= -2x^2+4

Answer 1

Answer:

positive point: $(0,\sqrt{2})$

negative points: $(0,-\sqrt{2})$.

Step-by-step explanation:

Factorize the given expression.

$f(x)=-2x^2+4\\f(x)=-2(x^2-2)\\f(x)=-2(x-\sqrt2)(x+\sqrt{2})$

Set the function equals to zero.

$-2(x-\sqrt2)(x+\sqrt{2})=0\\x=\sqrt{2}, -\sqrt{2}$

So, the positive point is $(0,\sqrt{2})$ and negative points is $(0,-\sqrt{2})$.