Answer:
def one_dimensional_booleans(bool_list, use_and):
is_all_true = True
is_one_true = False
if use_and:
for b in bool_list:
if b == False:
is_all_true = False
break
if is_all_true:
return True
else:
return False
else:
for b in bool_list:
if b == True:
is_one_true = True
break
if is_one_true:
return True
else:
return False
Explanation:
Create a function named one_dimensional_booleans that takes two parameters, bool_list and use_and
Inside the function:
Set is_all_true as True and is_one_true as False. These will be used to check the list
If use_and is True, check each item in the bool_list. If one item is False, set the is_all_true as False and stop the loop. This implies that the list contains a False value. Then check the is_all_true. If it is True, return True. Otherwise, return False.
If use_and is False, check each item in the bool_list. If one item is True, set the is_one_true as True and stop the loop. This implies that the list contains a True value. Then check the is_one_true. If it is True, return True. Otherwise, return False.
it depends on the kind of police check. like if its a road block type of check, they make sure everything is right. if you get pulled over you get your name ran in the system to check if you have warrents or warning and depends on what you get pulled over for, you could get a ticket or detained.
Answer:
The answer is "Option a"
Explanation:
Meta-character is a unique character, which is used in the system or information area, that provides information about the other characters. This type of character is used in both command-line and programming.
- It has a particular meaning and should be prevented for reasons except for its particular importance.
- It attempts in the algorithmic technique to view all character as a fundamental ASCII instead of a specific purpose.
When you are trying to solve a formula like this one, you need to consider the whole row in the spreadsheet, not just A1 and D1.
So, A1:D1 refers to the whole row, which means that you need to add A1+B1+C1+D1 = 2 + 1 + 5 + 3 = 11.
The answer to the formula according to this spreadsheet is 11.
