You my son the answer would’ve my cuh
The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.
Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.
By the fundamental theorem of calculus,

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so


To do this, you can just multiply across. 3 times 1 equals 3 so your numerator is 3. 2 times 4 equals 8. Then, your answer would be 3/8. Hope this helps :)
Take the expression x^2/3 which has an exponent of 2/3. The top of the fraction refers to the power - that is x^2 ( x squared). and the 3 indicates a cubic root.
So in radical form it is ∛(x^2)
Converting radical to exponent an example would be
∛(x^5) = x^(5/3)