2x-x+7=x+3+4 please help find the x

Mathematics

1 answer:

lord [1]3 years ago

7 0

Answer:

Step-by-step explanation:

2x-x+7 = x+3+4

2x-x-x = -7+3+4

2x-2x = -4+4

0 = 0

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On the 1st Jan 2012 Beth invested some money into a bank account.

mixer [17]

Account on 2014 is £17,466 when multipliled by 0.025 (interest per year) it will result to £436.65. So the money she had excluding the interest of the said year is £17,029.35 (17,466 - 436.65).
Going back to 2013, she withdraws £1000. If she has £17,029.35 in 2014, we can add £1000 to get £18, 029.35.If we take 2.5% from £18, 029.35. (18,029.35. x 0.025) the result is £450.73. Excluding the interest of year 2013, the money amounts to £17,578.62 (18,029.35 - 450.73), which is the original invested amount on her bank account from year 2012.

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3 years ago

Write the ratio in simplest form:<br> 36 to 78

Marysya12 [62]

Answer:

18 : 39

Step-by-step explanation:

36 to 78

Divide both sides by 2.

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2 years ago

Read 2 more answers

Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5

zaharov [31]

Answer:

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

$\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}$ or $\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}$

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

$\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}$

Therefore, the solution is 31.

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Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as $\displaystyle \large{a_{n-1} \cdot r = a_n}$ meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as: