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Ivahew [28]
2 years ago
6

Solve w=x/y-x for x.

Mathematics
1 answer:
lesya [120]2 years ago
5 0

Answer:

Rewrite the equation as x+xyz=wx+xyz=w.

x+xyz=wx+xyz=w

Subtract xx from both sides of the equation.

xyz=w−xxyz=w-x

Divide each term by xzxz and simplif

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PLEASE HELP!
Alexeev081 [22]
Rewrite as:
4y=x^2-12x+68
divide by four:
y= x^2/4-3x+17
your answer would be 
(6,8)
3 0
3 years ago
Determine the slope and y intercept. Y=3/2x+3
Harlamova29_29 [7]

Slope: 3/2 (the coefficient of x)

Y-Intercept: (0,3) (substituting x = 0 into the equation)

Ans: Yellow

7 0
3 years ago
If a point has a negative x-coordinate, and its y-coordinate is positive, where does the point lie relative to the origin? Expla
Daniel [21]
      If a coordinate has a negative x-coordinate and its y-coordinate is positive, then the point  is on the 2nd quadrant.
      That means that the point is left of the origin and above it.
4 0
3 years ago
Special Right Trianglws
Masteriza [31]

Answer:

x = 2\sqrt7

y = 2\sqrt7

Step-by-step explanation:

Hello!

This is a right isosceles triangle (45°-45°-90°). You can solve for the missing angle by simply subtracting 45° and 90° from 180° (sum of angles in a triangle equals 180°)

Since the triangle is isosceles, x and y are congruent because they are the legs opposite to the congruent angles.

In a right isosceles triangle, the hypotenuse is always the measure of one leg multiplied by \sqrt2.

So, let's use leg y, y\sqrt2 = 2\sqrt{14}

Solve for y:

y\sqrt2 = 2\sqrt{14}\\\\y = $\frac{2\sqrt{14}}{\sqrt2}$\\\\y = 2\sqrt7

y = 2\sqrt7, which means that x is also 2\sqrt7

3 0
2 years ago
PLSSS HELP MEE SHOW UR WORK!!
kumpel [21]

Answer:

(-3, 13)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -4x + 1

11y = x + 146

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                                                                                                  11(-4x + 1) = x + 146
  2. Distribute 11:                                                                                                      -44x + 11 = x + 146
  3. [Addition Property of Equality] Add 44x on both sides:                                11 = 45x + 146
  4. [Subtraction Property of Equality] Subtract 146 on both sides:                      -135 = 45x
  5. [Division Property of Equality] Divide 45 on both sides:                              -3 = x
  6. Rewrite/Rearrange:                                                                                          x = -3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                                                                                 y = -4x + 1
  2. Substitute in <em>x</em>:                                                                                                 y = -4(-3) + 1
  3. Multiply:                                                                                                           y = 12 + 1
  4. Add:                                                                                                                    y = 13
6 0
3 years ago
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