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vfiekz [6]
3 years ago
9

The graph of a proportional relationship passes through the point (5, 2) . What is the constant of proportionality of the relati

onship?
Mathematics
2 answers:
Vladimir79 [104]3 years ago
7 0

Answer:

2/5

Step-by-step explanation:

x = 5

y = 2

y = cx

2 = c × 5

c = 2/5

So, the constant of proportionality of the relationship is 2/5

serious [3.7K]3 years ago
3 0

Answer:

  • 2/5

Step-by-step explanation:

<u>Proportional relationship is:</u>

  • y = kx, where k is the constant of proportionality

We have a point (5, 2). it means x = 5, y = 2

<u>Substitute x and y and find k:</u>

  • 2 = k*5
  • k = 2/5
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The probability that Barry Bonds hits a home run on any given at-bat is 0.16, and each at-bat is independent.
serious [3.7K]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that p = 0.16

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136&#10;

0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

E = \frac{n}{p}

In this question, n = 1, p = 0.16. So

E = \frac{1}{0.16} = 6.25

The expected number of at-bats until the next home run is 6.25.

6 0
3 years ago
What is the value of one divided by zero?
Soloha48 [4]

Answer:

5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Apples cost $0.75 per pound and bananas cost $1.05 per pound.
dedylja [7]

Answer:

The baker bought 8 pounds of apples and 4 pounds of bananas.

Step-by-step explanation:

a+b=12.

0.75a+1.05b=10.20

First, multiply 2 my 10.

75a+105b=1020.

Then multiply 1 by 75.

75a+75b=900.

Then subtract.

75a+105b=1020

75a+75b=900.

75a-75a+105b-75b=1020-900

30b=120

b=4

Substitute into (1)

a+4=12

a=8.

Hope this helps :)

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3 years ago
Blake is working his way through school. he works two part time jobs for a total of 31 hours a week. job pays $5.80 per hour and
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are their any answer choices?

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3 years ago
Gretchen paid 2,5, and 3 dollors if she paid 4 dollors for each at a sale
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40 I am pretty sure that is the right answer
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