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astra-53 [7]
2 years ago
7

HELP ME ASAP!!!!!! See pic attached

Mathematics
1 answer:
icang [17]2 years ago
4 0

Step-by-step explanation:

a ) 9 × 2 = 18 → 18 + 3 = 21

o/p = 21

b) 17 - 3 = 14 → 14/2 = 7

i/p = 7

hope this answer helps you dear!

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What is the value of the following expression? 2w - 6, when w = 6
lara31 [8.8K]

Answer:

The answer is 6.

Step-by-step explanation:

Since w = 6 you would input the 6 where the w value is. Your equation should look like this: 2(6)-6

First you multiple the 2 x 6 which equals 12. After you minus 12-6 which equals 6. Therefore your answer is 6.

3 0
3 years ago
Write an expression for the operation described below.<br><br><br> multiply 6 by u
Masteriza [31]

Answer:

6u

Step-by-step explanation:

it is the algebraic answer.

hope this helps!

4 0
3 years ago
Read 2 more answers
plz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help
Volgvan

Answer:

the answer should be 9

Step-by-step explanation:

(256 * 3^{-5} * 6^{0} )^{-2} * (\frac{3^{-2}}{2^{3}} )^{4} * 2^{28}

(256*\frac{1}{3^{5}} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

(256*\frac{1}{243} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

(\frac{256}{243} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

(\frac{256}{243})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

(\frac{243}{256})^{2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

\frac{59049}{65536}*(\frac{1}{2^{3}*3^{2}})^{4}*2^{28}

\frac{59049}{65536}*(\frac{1}{8*9})^{4}*2^{28}

\frac{59049}{65536}*(\frac{1}{72})^{4}*2^{28}

\frac{59049}{65536}*\frac{1}{26873856}*2^{28}

\frac{9}{65536}*\frac{1}{4096}*2^{28}

\frac{9}{65536*4096}*2^{28}

\frac{9}{268435456}*268435456

9

6 0
3 years ago
Read 2 more answers
An automobile dealer had 288 cars and trucks in stock during the month. He must pay an inventory fee of 52 per car and $5 per tr
Aleonysh [2.5K]

For the given conditions, we won’t get a practical solution.

<u>Solution:</u>

Given, An automobile dealer had 288 cars and trucks in stock during the month.  

He must pay an inventory fee of 52 per car and $5 per truck.  

He paid $849 for inventory foes.  

We have to find how many cars and Trucks did he have during the month?

Now, let the number of trucks be n, then number of cars will be 288 – n

And, according to given information,

\begin{array}{l}{5 \times n+52 \times(288-n)=849} \\\\ {\rightarrow 5 n+52 \times 288-52 n=849} \\\\ {\rightarrow 52 n-5 n=14976-849} \\\\ {\rightarrow 47 n=14127} \\\\ {\rightarrow n=300.57}\end{array}

Here we got n > number of cars and trucks, which is practically impossible.  

Hence, for the given conditions, we won’t get a practical solution

8 0
3 years ago
The distance between two towns is 21.673 km. Round of the distance to nearest 0.01 km.
Andreyy89

Answer: 21.67 km

Step-by-step explanation:

3 0
3 years ago
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