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nydimaria [60]
3 years ago
5

David gets 65 chocolates an hour for cleaning. He gets a 15% raise. He cleans for 60 hours this week. How many more chocolates w

ill he get this week as a result of his raise?
Mathematics
2 answers:
nalin [4]3 years ago
5 0

Answer:

4485

Step-by-step explanation:

60 x 65 is equivalent to 3900, but since he got a raise, it would add 15% more to 3900, which is 4485 chocolates this week

  60

x 65

_____

     0

  3900

Xelga [282]3 years ago
5 0
The answer is 4485, you have to multiply 60 x 65 which is 3900 but you have to also add the raise which was 15% therefore when you add all that together you get 4485 :)
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iris [78.8K]
5.8 * 10^7

2.5* 10 ^ -3
5 0
3 years ago
Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
Jessica bought 12 pieces of candy at the store for $0.65 each. How much did she spend in all?
vichka [17]

You just do 12•.65. Then that’s your answer.

6 0
3 years ago
Read 2 more answers
Solve for x. 5x - 1 = 26 x = x = 5 x = -5
Doss [256]

Answer:

x = 27/5

Step-by-step explanation:

5x - 1 = 26

Add 1 to each side

5x - 1 = 26

5x-1+1 = 26+1

5x = 27

Divide each side by 5

5x/5 = 27/5

x = 27/5

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3 years ago
Adult tickets to the fall play cost $6 and student tickets cost $3. The drama class sold 25 more student tickets than adult tick
svlad2 [7]

9514 1404 393

Answer:

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  • 65 adult tickets

Step-by-step explanation:

For many "mixture" problems, it is convenient to use a variable for the quantity of the highest contributor. Here, we can use 'a' to represent the number of adult tickets, because adult tickets cost the most. Then the number of student tickets is (a+25), and the total revenue is ...

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  a = 65

  (a+25) = 90

The drama class sold 90 student tickets and 65 adult tickets.

6 0
3 years ago
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