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2 years ago

Please help me. Are my answers right?

Mathematics

2 answers:

Makovka662 [10]2 years ago

6 0

Where is the question??

V125BC [204]2 years ago

3 0

I’m sorry but I don’t see the paper or the homework that you have

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What ate all the numbers that round to 240

kramer

248 243 247 246 245 249

5 0

3 years ago

Please help me! I will give brainly!

Viktor [21]

<h3>Answer: 0.34</h3>

============================================================

Explanation:

A = 0.61 is given to us

Pumpkin B travels 0.28 of a mile further than A does, so,

B = A+0.28 = 0.61+0.28 = 0.89

Pumpkin B travels 0.89 of a mile.

---------------------

Pumpkin C travels 0.06 of a mile more than B does, which means,

C = B + 0.06

C = 0.89 + 0.06

C = 0.95

Pumpkin C travels 0.95 of a mile.

---------------------

The last thing to do is to subtract the values of C and A

C - A = 0.95 - 0.61 = 0.34

Pumpkin C travels 0.34 of a mile further compared to pumpkin A.

---------------------

Side note: if you want to convert from miles to feet, then multiply by 5280.

For instance, 0.61 miles = 0.61*5280 = 3,220.8 feet.

5 0

3 years ago

Read 2 more answers

Jake asked 25 students in his class how close they live to school .the frecuencia table shows the results

Oliga [24]

That's great so what the question

7 0

3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

2 years ago

Study the graph of f(x) = 10x. Use the drop-down menus to identify the lines that represent the functions below. p(x) = 10(x + 4

sasho [114]

Answer:

1 (line B)

2 (line A)

3 (line D)

Step-by-step explanation: We both know I don't have one.

3 0

3 years ago

Please help me. Are my answers right? ​

Please help me. Are my answers right?