First, you would have to plug 3 into the equation
15-(3)/9-(3)
Then do the math
12/6
This can be simplified, since 12 and 6 are divisible by 6, which is their greatest common factor
2/1
So the answer is D. 2
Hope this helps!
The following set of data represents letter grades on term papers in a rhetoric class: A,A,A,B,B,B,B,C,C,C,C,C,C,C,C,C,D,D,D,F.
Viktor [21]
Answer:
c. Mode
Step-by-step explanation:
Mean is the average obtained by adding all values and then dividing by the size of the values. Here, adding A and B etc is not clear.
Median is the middle value of a set of numeric values. To find a median, values should be sort-able from smallest to the largest. If there is no unique middle value, then the average of the middle values has to be taken. Here, average of the two different grades is not clear.
Mode is the value that occurs most often. Clearly C occurs most often.
Mid-range value is the mean of the difference between largest value and the smallest value. Here, difference between A and F is not clear.
Mean,median,Mid-range are applied to numeric values where mode is also suitable for categorical values.
Therefore, the most appropriate measure of central tendency for the data described is mode
2a+3=s
I used the first letter of the name, or you can use x and y in place of a and s
Answer:
2.8- 4.4n- 2n + 7 = -6.4n + 9.8
Step-by-step explanation:
combined like term:
-4.4n - 2n = -6.4n
2.8 + 7 = 9.8
so all you do is combined together and got -6.4n + 9.8
The first letter can be any one of 26 letters. For each one . . .
The second letter can be any one of 26 letters. For each one . . .
The first digit can be any one of 10 digits. For each one . . .
The second digit can be any one of 10 digits. For each one . . .
The third digit can be any one of 10 digits. For each one . . .
The fourth digit can be any one of 10 digits. For each one . . .
The fifth digit can be any one of 10 digits.
The total number of possibilities is
(26 x 26 x 10 x 10 x 10 x 10 x 10) =
( 26² x 10⁵) = (676 x 100,000) = <em>67,600,000</em> .
