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3 years ago

Please someone help me with this! Giving brainliest :)

Mathematics

2 answers:

Ilya [14]3 years ago

8 0

Answer:

nswer: x = 0

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

olga2289 [7]3 years ago

3 0

Answer:

$n=3$

Step-by-step explanation:

Note that $2^5*5^2=2^3*2^2*5^2=2^3*(2*5)^2=2^3*10^2$ .

Aha! We see a path to the solution!

We now know that our equation is actually $2^3*10^2=2^{n}*10^2$ .

We can divide both sides by $10^2$ to get $2^3=2^{n}$ .

By inspection or taking the logarithm base 2 of both sides, we see that $3=n$ .

So, the answer is $\boxed{n=3}$ and we're done!

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At the beginning of the first day, Ann has 25 dollars. By the end of the first day, Ann has 2/3 of the money that she had at the

ira [324]

Answer:

Ann have at the end of the second day $\$9\frac{11}{21}.$

Step-by-step explanation:

Given:

At the beginning of the first day, Ann has 25 dollars.

By the end of the first day, Ann has 2/3 of the money that she had at the beginning of the first day.

By the end of the second day, Ann has 4/7 of the money that she had at the end of the first day.

Now, to find the money Ann have at the end of the second day.

Ann has at the beginning of the first day = $25.

At the end of the first day Ann had:

$\frac{2}{3} \ of\ 25$

$=\frac{2}{3} \times 25$

$=\$\frac{50}{3} .$

So, at the end of the first day Ann had $=\$\frac{50}{3} .$

Now, to get the money Ann have at the end of the second day:

$\frac{4}{7} \ of\ \frac{50}{3}$

$=\frac{4}{7} \times \frac{50}{3}$

$=\frac{200}{21}$

$=\$9\frac{11}{21} .$

Therefore, Ann have at the end of the second day $\$9\frac{11}{21}.$

8 0

4 years ago

Solve for x 3/4+x=1/2 Simplify your answer

lukranit [14]

Step 1. Subtract 3/4 from both sides

x = 1/2 - 3/4

Step 2. Simplify 1/2 - 3/4 to -1/4

x = -1/4

7 0

3 years ago

If 3220 = 80+7, what is the value of c?

Setler79 [48]

Answer:

Correct option is

36.25

Modal class =30−40

So we have, l=30,f0=12,f1=32,f2=20 and h=10

⇒ Mode=l+2f1−f0f2f1−f0×h

=30+2×32−12−2032−12×10

=30+6.25

=36.25

∴ Mode =36.25

8 0

3 years ago

Solve the system of equations by graphing on your own paper. Write the

Verdich [7]

Answer:

(9, -1)

Step-by-step explanation:

7 0

3 years ago

used books cost $2.27 each. which represents the total number of books that can be purchased for $10?

siniylev [52]

Answer:

4 books

Step-by-step explanation:

The cost for one used = $2.27

The question requires you to find the number of books that could be purchased with $10

Let assume the cost for a single used book to be $ t

If you have $ x in your pocket then the number of books you can purchase with $ x will be;

number of books= $ x/ $t.............................(a)

Applying this expression to the question;

$t= $2.27

$ x= $10

number of books = $10/$2.27 = 4.405 = 4 books

4 0

3 years ago

Read 2 more answers