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3 years ago

How you would divide. 17.6 = 3.2?

Mathematics

1 answer:

elena55 [62]3 years ago

6 0

Step-by-step explanation:

he has a long way from a few months to a month or two before he gets a chance at a time of his life in a way he would be able and to see his own son in the middle east as the president and the invincible president and his family

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55/3 as a mixed number

Firdavs [7]

to get the mixed number just divide the numerator by the denominator;

55 ÷ 3 = 18 1/3

7 0

3 years ago

A veterinarian’s assistant made a table that shows the animals seen in the office in one week. What is the probability that the

horsena [70]

Answer:

The probability that the pet seen was sick is 53.57%.

Step-by-step explanation:

The probability of an event E is the ration of the number of favorable outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = number of favorable outcomes

N = total number of outcomes

Denote the events as follows:

C = the pet is a cat

D = the pet is a dog

O = the pet is some other animal

S = the pet is sick.

The data provided is summarized as follows:

n (C) = 28

n (C ∩ S) = 3

n (D) = 42

n (B ∩ S) = 4

n (O) = 24

n (O ∩ S) = 8

Compute the probability that a cat was sick as follows:

$P(C\cap S)=\frac{n(C\cap S)}{n(C)}=\frac{3}{28}$

Compute the probability that a dog was sick as follows:

$P(D\cap S)=\frac{n(D\cap S)}{n(D)}=\frac{4}{42}=\frac{2}{21}$

Compute the probability that another animal was sick as follows:

$P(O\cap S)=\frac{n(O\cap S)}{n(O)}=\frac{8}{24}=\frac{1}{3}$

Compute the probability that the pet seen was sick as follows:

P (S) = P (C ∩ S) + P (D ∩ S) + P (O ∩ S)

$=\frac{3}{28}+\frac{2}{21}+\frac{1}{3}\\=\frac{9+8+28}{84}\\=\frac{45}{84}\\=0.5357$

Thus, the probability that the pet seen was sick is 53.57%.

8 0

4 years ago

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HELPPP PLSSSSSSSSS and thank youuu

vitfil [10]

Answer:

Answer is The last one angle DFE

3 0

3 years ago

Orange traffic cones come in a variety of sizes. Approximate the volume, in cubic inches, of a traffic cone that has a height of

Irina18 [472]

Answer:

Volume of the cone = 628 cubic inches.

Step-by-step explanation:

Given:

Height of the traffic cone, $h$ = 2 feet = 24 inches ...[1 feet =12 inches]

Diameter of the cone, $d$ = 10 inches

Radius of the cone, $r$ = 5 inches ...[ $r=\frac{d}{2}$ ]

Value of pie, $\pi$ = 3.14

We have to find the approximate volume.

Lets say that the volume is $V$ .

Formula:

Volume of a cone = $\frac{\pi r^2h}{3}$

So,

⇒ $V=\frac{\pi r^2h}{3}$

⇒ Plugging the values.

⇒ $V=\frac{3.14\times 5^2\times 24}{3}$

⇒ $V=\frac{3.14\times 25\times 24}{3}$

⇒ $V=628$ $inches^3$

The volume of the orange traffic cone is 628 inches^3.

8 0

3 years ago

30minutes = how many seconds

AURORKA [14]

30min(60sec/min)=1800sec

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3 years ago

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