Answer:
27 and 16
Step-by-step explanation:
x + y = 43
x - y = 11
You can add up the two equations so the ys are cancelled out.
2x = 54
x = 27
Plug x in to find y.
27 - y = 11
y = 16
<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
Answer:
Step-by-step explanation:
A = C^2 / 4 x pi
so if the circumfernce was 10 you would square it to make it 100 and then you would do 4 x pi to get 12.57 ( rounded).
you would then just divide 100 by 12.57 = 7.96 ( rounded)
hope it helped
X=4.1
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First you would solve for h(5) by plugging in 5 as your x, then solving it.
h(5) = 5^2 + 1
h(5) = 25 + 1
h(5) = 26
Next you would multiply the 26 by the individual h, which is basically h(1).
h(1) = 1^2 + 1
h(1) = 2
Lastly you multiply your h(1) value by the h(5) value to get your answer.
h(1) • h(5) = 26 • 2
h[h(5)] = 52