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3 years ago

If the greatest value of n is 8, which inequality best shows all the possible values of n? n < 8 n > 8 n ≤ 8 n ≥ 8

Mathematics

1 answer:

padilas [110]3 years ago

6 0

The greatest value is 8, which means n can be either 8 or any number less than 8.

The inequality would be n is less than or equal to 8, which is written as:

n ≤ 8

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Fill in the blank to solve the equation below <br><br> 12 + 24 = 2(6 + _)

Dimas [21]

Answer:

12 + 24 = 2(6 + 12)

Step-by-step explanation:

hope this helpss :D

much appreciated if this were marked brainliest <3

4 0

3 years ago

Read 2 more answers

Suppose the weights of tight ends in a football league are normally distributed such that σ2=400. A sample of 11 tight ends was

AlladinOne [14]

Answer:

$217.636-1.96\frac{20}{\sqrt{11}}=205.817$

$217.636+1.96\frac{20}{\sqrt{11}}=229.455$

So on this case the 95% confidence interval would be given by (205.82;229.46)

Step-by-step explanation:

Assuming the following data: Weight 150 169 170 196 200 218 219 262 269 270 271

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma= \sqrt{400}= 20$ represent the population standard deviation

n=11 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

In order to calculate the mean we can use the following formula:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

The mean calculated for this case is $\bar X=217.636$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$217.636-1.96\frac{20}{\sqrt{11}}=205.817$

$217.636+1.96\frac{20}{\sqrt{11}}=229.455$

So on this case the 95% confidence interval would be given by (205.82;229.46)

8 0

3 years ago

Solve this problem on paper using all four steps.

ratelena [41]

Your mistake is that week 3 is twice of week 2
week2=x+5, twice of that is 2(x+5)=2x+10, you did not distribute the 2 to the 5 and you got 2x+5, that is your mistake

x is first week
2nd week is y
3rd is z

5 more the 2nd week than 1st week
x+5=y

3rd week is double 2nd wee
z=2y

total is 431

x+y+z=431
sub
y=5+x and z=2y
x+5+x+2y=431
sub 5+x for y
x+5+x+2(5+x)=431
x+5+x+10+2x=431
4x+15=431
minus 15
4x=416
divide by 4
x=104
add 4
x+5=109
double
2*109=218

they sold
1st week: 104
2nd week: 109
3rd week: 218

3 0

3 years ago

Read 2 more answers

WILL UP VOTE!!!

9966 [12]

Here you go. Hope you understand all of the work.

5 0

3 years ago

What would be the solution to this Pythagorean/Trigonometric equation? (csc² A - 1) sen² A = cos² A

Anna007 [38]

Answer:

$(csc^2 A -1) sin^2 A = cos^2 A$

We know that $csc x= \frac{1}{sin x}$ and using this identity we have:

$\frac{sin^2 A}{sin^2 A} - sin^2 A = cos^2 A$

$1 = cos^2 A + sin^2 A$

And if we remember the equation above represent the fundamental identity in trigonometry and is satisfied for every real number and we can say that the solution for this case is:

$A= [X | x \in R]$

Step-by-step explanation:

For this case we have the following equation given:

$(csc^2 A -1) sin^2 A = cos^2 A$

We know that $csc x= \frac{1}{sin x}$ and using this identity we have:

$\frac{sin^2 A}{sin^2 A} - sin^2 A = cos^2 A$

$1 = cos^2 A + sin^2 A$

And if we remember the equation above represent the fundamental identity in trigonometry and is satisfied for every real number and we can say that the solution for this case is:

$A= [X | x \in R]$

8 0

4 years ago