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Ratling [72]
3 years ago
5

If the middle number is lesser than the candidates then u eliminate the ___ half of the data​

Computers and Technology
1 answer:
lutik1710 [3]3 years ago
7 0

Answer:

kimochisiwiwie282828

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Explanation:

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3 years ago
Two electronics technicians are looking at the piece of testing equipment shown in the figure above. Technician A says that this
Ilya [14]
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Write a program whose input is two integers. Output the first integer and subsequent increments of 5 as long as the value is les
adell [148]

Answer:

Following are the code to the given question:

For code 1:

start = int(input())#defining a start variable that takes input from the user end

end = int(input())#defining a end variable that takes input from the user end

if start > end:#use if that checks start value greater than end value

   print("Second integer can't be less than the first.")#print message

else:#defining else block

   while start <= end:#defining a while loop that checks start value less than equal to end value

       print(start, end=' ')#print input value

       start += 5#incrementing the start value by 5

   print()#use print for space

For code 2:

while True:#defining a while loop that runs when its true

   data = input()#defining a data variable that inputs values

   if data == 'Done' or data == 'done' or data == 'd':#defining if block that checks data value

       break#use break keyword

   rev = ''#defining a string variable rev

   for ch in data:#defining a for loop that adds value in string variable  

       rev = ch + rev#adding value in rev variable

   print(rev)#print rev value

Explanation:

In the first code two-variable "first and end" is declared that takes input from the user end. After inputting the value if a block is used that checks start value greater than end value and use the print method that prints message.

In the else block a while loop is declared that checks start value less than equal to end value and inside the loop it prints input value and increments the start value by 5.

In the second code, a while loop runs when it's true and defines a data variable that inputs values. In the if block is used that checks data value and use break keyword.

In the next step, "rev" as a string variable is declared that uses the for loop that adds value in its variable and prints its values.

3 0
3 years ago
When preparing images to be used for different mediums print web and video in photoshop different file formats are required , se
Anika [276]
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TIFF - Can be saved in an uncompressed file format with a high resolution, it is a common file format used for professional print services
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5 0
3 years ago
"Write an iterative function iterPower(base, exp) that calculates the exponential baseexp by simply using successive multiplicat
sp2606 [1]

Answer:

I am writing the function using Python. Let me know if you want the program in some other programming language.            

def iterPower(base, exp):    

    baseexp = 1

    while exp > 0:

        baseexp = baseexp*base

        exp= exp - 1

    return baseexp

base = 3

exp = 2

print(iterPower(base, exp))

Explanation:

  • The function name is iterPower which takes two parameters base and exp. base variable here is the number which is being multiplied and this number is multiplied exponential times which is specified in exp variable.
  • baseexp is a variable that stores the result and then returns the result of successive multiplication.
  • while loop body keeps executing until the value of exp is greater than 0. So it will keep doing successive multiplication of the base, exp times until value of exp becomes 0.
  • The baseexp keeps storing the multiplication of the base and exp keeps decrements by 1 at each iteration until it becomes 0 which will break the loop and the result of successive multiplication stored in baseexp will be displayed in the output.
  • Here we gave the value of 3 to base and 2 to exp and then print(iterPower(base, exp)) statement calls the iterPower function which calculates the exponential of these given values.
  • Lets see how each iteration works:
  • 1st iteration

baseexp = 1

exp>0 True because exp=2 which is greater than 0

baseexp = baseexp*base

               = 1*3 = 3

So baseexp = 3

exp = exp - 1

      = 2 - 1 = 1    

exp = 1

  • 2nd iteration

baseexp = 3

exp>0 True because exp=1 which is greater than 0

baseexp = baseexp*base

               = 3*3 = 9

So baseexp = 9

exp = exp - 1

      = 1-1 = 0    

exp = 0

  • Here the loop will break now when it reaches third iteration because value of exp is 0 and the loop condition evaluates to false now.
  • return baseexp statement will return the value stored in baseexp which is 9
  • So the output of the above program is 9.
5 0
3 years ago
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