<h2>Answer:</h2>
When the crossing over results in both mutant alleles on one chromosome and the other chromosome will be mutation free.
<h3>Explanation:</h3>
During the meiosis chromosomes are present in homologous form in a pair.
They exchange their genetic material with each other. This exchange is random and usually genetic material on the ends/telomere changes with the homologous chromosome.
In given condition the exchange is in such manner that the mutant allel of one chromosome shifts to other during crossing over. While other chromosome also contains its own mutant allele and does not exchange it during crossing over.
Decomposition is the process that plays an important role in cycles of carbon and nitrogen
Answer:
Option C
Explanation:
Let the allele for black color be "B"
and the allele for white color be "b"
Since after F1 generation all the offspring have black body with white speckles throughout their feathers.
Thus the allele for black and white show co dominance.
Genotype of parent after F1 generation would be Bb for speckled chickens
Cross between two specked adults will produce -
Bb x Bb
BB, Bb, Bb, bb
Out of four offspring 1 is black (BB), 1 is white (bb) and two are speckled (Bb)
Thus 50% of the offspring will be speckled, 25% will be black, and 25% will be white.
Option C is correct
A. A statement of purpose
It gives the plant ENOUGH oxygen to help it
