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3 years ago

1 half dollar + 1 quarter - 2 dimes

Mathematics

1 answer:

Eduardwww [97]3 years ago

7 0

Answer:

55 cents.

Step-by-step explanation:

First, we start off with a half dollar (50 cents), and add a quarter (25 cents). 50 + 25 = 75. Next we take two dimes (each dime being 10 cents). 10 + 10 is 20, so we have twenty cents in dimes. It says to subtract the 2 dimes from our current number 75 minus 20 is 55. Therefore, we have 55 cents left. (If needed, that is 1 half dollar and 1 nickel.)

Hope this helps! :D

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A bamboo shoot is 20 inches tall at the zero and gross 24 inches each day which functions show below can be used to determine he

ale4655 [162]

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A gift box measures 8 inches by 10 inches by 3 inches. what is the surface area of the box?

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Answer:

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Step-by-step explanation:

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4 years ago

Write an equation of the line that passes through (18, 2) and is parallel to the line 3y - x = -12

GarryVolchara [31]

First you need to find the slope.
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Gummi bears come in twelve flavors, and you have one of each flavor. Suppose you split your gummi bears among three people (Adam

aliina [53]

Step-by-step explanation:

From the given gummi bear, the chance that Adam is selected for any draw is 1/3 as well as the chance he is not selected at any draw is 2/3.

a). The probability of Adam getting exactly three gummi bears = P(Adam gets selected at 3 draws and not selected at the remaining 9 draws)

= $(\frac{1}{3})^3 (\frac{2}{3})^9 = \frac{2^9}{3^{12}}$

Now, the 3 draws where Adam gets selected can be any 3 out of 12 draws in ${\overset{12}C}_3$ = 220

Thus, probability of Adam getting three gummi bears = $220 \times \frac{2^9}{3^{12}}$

= 0.21186

b). Probability that Adam will get the three gummi bears given each person will received at the most 1 gummi bear

= P(of the remaining 9 draws after assigning one gummi bear to each one, Adam gets selected at 2 draws and not selected at 7 draws) = ${\overset{9}C}_2 (\frac{1}{3})^2 (\frac{2}{3})^7$

= 0.23411

c). Let X = Number of the gummi bears which Adam will get. Then, X = number of draws out of 12 draws Adam gets selected and X ~ B(12, 1/3). So, Adam will get gummi bears= mean of B(12, 1/3) = 12 x (1/3) = 4

d). Let Y = Number of the gummi bears that Adam will get, given each person will received at the most 1 gummi bear Then, Y = number of draws Adam gets selected in the remaining 9 draws and Y ~ B(9, 1/3). So, the expected number of bears that Adam gets given each person received at least 1 gummi bear

= 1 + mean of B(9, 1/3) = 4

e). When every one gets atleast one gummi bear, the new sample size will be 9 and so we can say that there is a reduction in variance.

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