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2 years ago

5

Jose takes a job that offers a monthly starting salary of $2500 and guarantees him a monthly raise of 130$ during his first ye

ar of training. Find the general term of this arithmetic sequence and his monthly salary at the end of his training.
The general term of this arithmetic sequence is
nothing.

1 answer:

Leto [7]2 years ago

7 0

Look it up on quizzes

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Can u please help me with this

Art [367]

Answer:

Acute angle, 85 degrees. That's my guess I hope it helps.

7 0

2 years ago

Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e

svet-max [94.6K]

ANSWER

$y = 2x -4$

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

$x = 5 + ln(t)$

$y = {t}^{2} + 5$

From the first equation we make t the subject to get;

$x - 5 = ln(t)$

$t = {e}^{x - 5}$

We put it into the second equation.

$y = { ({e}^{x - 5}) }^{2} + 5$

$y = { ({e}^{2(x - 5)}) } + 5$

We differentiate to get;

$\frac{dy}{dx} = 2 {e}^{2(x - 5)}$

At x=5,

$\frac{dy}{dx} = 2 {e}^{2(5 - 5)}$

$\frac{dy}{dx} = 2 {e}^{0} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5)$

$y = 2x - 10 + 6$

$y = 2x -4$

Without eliminating the parameter,

$\frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }$

$\frac{dy}{dx} = \frac{ 2t}{ \frac{1}{t} }$

$\frac{dy}{dx} = 2 {t}^{2}$

At x=5,

$5 = 5 + ln(t)$

$ln(t) = 0$

$t = {e}^{0} = 1$

This implies that,

$\frac{dy}{dx} = 2 {(1)}^{2} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5) =$

$y = 2x -4$

5 0

3 years ago

Solve the equation 5*e^x=15.76

liq [111]

Divide both sides by 5

e^x=3.152 take the natural log of both sides...

x=ln(3.152)

x≈1.148

3 0

3 years ago

6. What is the result of multiplying the digit in the hundredths place by

Setler [38]

Answer:

B.9

Step-by-step explanation:

9*1=9

6 0

2 years ago

Saturn is 8.867 × 108 miles away from the Sun. Uranus is 1.787 × 109 miles away from the Sun. Approximately how many times farth

GrogVix [38]

Answer:

0.2 times

Step-by-step explanation:

Saturn: 8.867 × 108 = 957.636

Uranus: 1.787 × 109 = 194.783

You take (Uranus: 194.783)

& you divide it by (Saturn: 957.636)

You should get a funky number like 0.203399830415732 but since they said approximately you only need to use the first 2 (don't forget to round)

That would make Uranus 0.2 times as far from the sun

4 0

2 years ago