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Serhud [2]
2 years ago
7

I don’t understand this helpp

Mathematics
1 answer:
Olenka [21]2 years ago
4 0

Answer:

a. y2×

b.y1×

c.y1×

d.y2×

e.1×

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Write the sum of 18 + 27 as the product of their GCF and another sum <br><br> (PLEASE HELP)
nikdorinn [45]
27
18
----
45

GCF of 45 = 15 
Here is a word document on Greatest Common Factors and how to solve it.

Download docx
4 0
3 years ago
If there are 5 terms in a quadratic sequence
exis [7]

Answer:

7.2

Step-by-step explanation:

First differences:

0.8-0.2, 1.8-0.8, 3.2-1.8, 5.0-3.2

0.6, 1.0, 1.4, 1.8

Second differences:

1.0-0.6, 1.4-1.0, 1.8-1.4

0.4, 0.4, 0.4

For the next term, add 0.4 to the last term from the first differences, and add the sum to the last term of the quadratic sequence:

0.4+1.8=2.2

2.2+5.0=7.2

∴ The next term in the sequence is 7.2

7 0
3 years ago
The formula for the area of a square is s2, where s is the side length of the square. What is the area of a square with a side l
levacccp [35]

36

area of square = s²

given s = 6 , then

area = 6² = 36



8 0
3 years ago
Which description does NOT guarantee that a quadrilateral is a rectangle?
grandymaker [24]
The answer would be : A parallelogram with congruent sides does NOT guarantee that a quadrilateral is a rectangle  
7 0
3 years ago
Is there any video related to this or can you explain how to do it
uranmaximum [27]

Angles ECD  and CEF add to 180

40+140 = 180

So that means we have EF parallel to CD (due to the same side interior angle theorem)

--------------

Angles BCE and ECD combine to 30+40 = 70, which is congruent to angle ABC = 70 as well.

In other words, this shows angle ABC = angle BCD. Both of these angles are alternate interior angles. Since they're congruent, they lead to AB being parallel to CD.

--------------

So far we have

AB || CD

CD || EF

Using the transitive property, we can then link the two statements to say AB || EF. Think of a chain where CD is the common link. We go from AB to CD, then from CD to EF. So we can just take a single path from AB to EF.

It's like saying "P --> Q and Q --> R, therefore P --> R"

4 0
3 years ago
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