Using the formula below, find F, when f = 1000 and r = 8

Mathematics

2 answers:

Kaylis [27]3 years ago

5 0

Answer: 15.625

Step-by-step explanation:

F = 1000/(8^2) = 1000/64 = 15.625

Readme [11.4K]3 years ago

4 0

Answer:

F = 15.625

Step-by-step explanation:

This question may look quite tricky because of the square number, and fraction, but it is actually quite simple when you break it down.

To calculate this question we need to substitute the number 1000 (because we are told this is f) into where f is in our equation. Our new equation is F=1000/r^2.

Next, we need to substitute the number 8 (because we are told this is r) into where r is in our equation. Our new equation is F=1000/8^2.

At this stage, it is just a matter of putting this information directly into a calculator to find F. The answer we get is 125/8, and to get this is into decimal form, we just divide 8 by 125, and the answer is 15.625. This is our final answer.

<em>I have attached a photograph of this calculation written down.</em>

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3 years ago

A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.

melisa1 [442]

Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

$\overline{OB}:\overline{AB} = 1:2$
$\overline {OB}:10 = 1:2$
$\overline{OB} = \frac{1}{2}(10) = 5$

Similarly, we have

$\overline{AO}:\overline{AB} = \sqrt{3}:2$
$\overline {AO}:10 = \sqrt{3}:2$
$\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}$

Now, to find the lengths of the diagonals,

$\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}$
$\overline{BC} = 2(\overline{OB}) = 10$

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units