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Ganezh [65]
2 years ago
12

Professions Review and Quiz Test: Vocabulary and Grammar 1.7

Spanish
1 answer:
vovikov84 [41]2 years ago
4 0

Answer:

What type of question is this

Explanation:

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Simplify x^3-125/2x-10
MAVERICK [17]
We \ first, \ simplify \  \frac{125}{2} \\ \\   \left[\begin{array}{ccc}((x^3)-( \frac{125}{2}*x))-10 \end{array}\right] \\ \\ \boxed{\boxed{x^3= \frac{x^3}{1} = \frac{x^3*2}{2} }} \\ \\ \\ \boxed{ \frac{x^3*2-(125x)}{2} = \frac{2x^3-125x}{2} } \\ \\ \\ \frac{(2^3-125x}{2} -10 \\ \\  pulling \ out \ like \ factors : \\ \\  2x^3 - 125x  =   x * (2x^2 - 125) \\ \\ Factoring: \  2x^2 - 125

<span>Here's how!</span>

Proof :  \ (A+B) * (A-B) =\\&#10;         A2 - AB + BA - B2 =\\&#10;         A2 - AB + AB - B2 = \\&#10;         A2 - B2\\

<span>Therefore</span> . . . 

\boxed{ \frac{x*(2x^2-125)-(10*2)}{2} = \frac{2x^3-125x-20}{2} }

<span>The factors would then be the following:</span>

→ ( Leading \  Coefficient :  1,2)
→ (Trailing Constant) :  1 ,2 ,4 ,5 ,10 ,20

By then, understanding on how we have got in our terms, such as the like terms, and also how we have understanded the coefficient's, we would then have our answer clear below.

\leadsto \ Your \ answer: \boxed{\bf{ \frac{2x^3-125x-20}{2} }} <span>✔</span>
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