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Papessa [141]
2 years ago
8

Passing through (-2,-6) and parallel to the line whose equation is y=-3x+4

Mathematics
1 answer:
Licemer1 [7]2 years ago
6 0

Answer:

y = -3x - 12

Step-by-step explanation:

Lines that are parallel have the same gradient.

Therefore using the point (-2,-6) you can make your own equation.

-6 will be y, -2 will be x

All you have to do is find the y-intercept which is C in <em>y</em><em>=</em><em>mx</em><em>+</em><em>c</em>

-6 = -3(-2) + c

-6 = 6 + c

-12 = c

Therefore;

<u>y = -3x - 12</u>

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Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2
igor_vitrenko [27]

Answer:  The required solution of the given IVP is

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Step-by-step explanation:  We are given to find the solution of the following initial value problem :

y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.

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Then, we have

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This gives, after differentiating with respect to x that

y^\prime(x)=Ae^x-Be^{-x}.

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Adding equations (i) and (ii), we get

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4 0
3 years ago
Which equation represents the line shown
murzikaleks [220]

Answer: Third option:

Step-by-step explanation:

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y=mx+b

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The equation  in Slope Intercept form  of a line that passes through the Origin, is:

y=mx

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In this case you can observe in the picture attached that the line passes through the point (0,0).

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7 0
3 years ago
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Answer:

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Answer:

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So, total number of selections = 4 x 6 = 24

7 0
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