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3 years ago

Tell whether the lines are parallel, perpendicular, or neither.

Mathematics

2 answers:

EastWind [94]3 years ago

8 0

Line 1: y=4x-9
0=4x-9
-4x=-9
x=2,25

Line2: y=-4x+1
0=-4x+1
4x=1
x=0,25

viva [34]3 years ago

6 0

Answer:

See attachment ♪♪♪♪♪♪♪•

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Dots sells a total of 277 T-shirts ($2) and shorts ($3). In April, total sales were $656.

icang [17]

Answer:

Shorts = 112 and t shirts = 165

Step-by-step explanation:

Let S = shorts

Let T = t shirts

T + S = 277

$2T + $3S = $656

-2(T + S) = 277 so -2T -2S = -544

2T + 3S = 656 so 2T + 3S = 656

------------------------

SO: (subtract T's cancel out) 1S = 112

divide by 1 so S = 112

Plug S into the top equation: T + s = 277 T + 112 = 277 so T = 165

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3 years ago

A spinner travels around a circle. The radius is 3 inches. Mike spins the spinner and it travels completely around the circle 5

nignag [31]

Answer:

The spinner travelled 94.2 inches.

Step-by-step explanation:

In order to solve this question we first need to calculate the length of the circle, that is given by the following formula:

length = 2*pi*r

length = 2*3.14*3 = 18.84 inches

Since the spinner revolved around the circle 5 times, the distance travelled by the tip is the length of the circle multiplied by 5, as shown below:

distance = length*5

distance = 18.84*5 = 94.2 inches

The spinner travelled 94.2 inches.

7 0

3 years ago

Read 2 more answers

What is the perimeter of a rhombus whose diagonals measure 42cm and 56cm?

Trava [24]

Answer:

676

Step-by-step explanation:

d1×d2/2

42×56/2

1352/2=676

please check it by doing again

3 0

3 years ago

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An artist has completed 1 4 of a painting in 2 weeks. At what rate is she working? Simplify your answer and write it as a proper

Alika [10]

Answer:

1/8 because 1/4 x 1/2 = 1/8

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2 years ago

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$

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3 years ago