According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
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[6, -infinity)
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3.14?
or do you want more digits?
3.141592653589793238462643383279502884197169399375105820974944592307816406286<span> </span>
The gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².
<h3>What is the Total Surface Area of a Rectangular Box?</h3>
Total surface area (TSA) = 2(wl+hl+hw), where:
- l = length
- w = width
- h = height of the box.
The amount of gift wrap needed to cover the whole box = total surface area of the rectangular box
l = 20 in.
w = 8 in.
h = 13 in.
Plug in the values into the formula for total surface area of a rectangular box:
TSA = 2(8×20 + 13×20 + 13×8)
TSA = 1,048 in.²
Therefore, the gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².
Learn more about rectangular box on:
brainly.com/question/13103197
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