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Triss [41]
2 years ago
6

The value of y is directly proportional to the value of x. When x=3.5, the value of y is 14. What is the value of y when x = 28?

Mathematics
1 answer:
inna [77]2 years ago
7 0

Answer:

x = 7

Step-by-step explanation:

y = 14

14 x 2 = 28

Therefore:

3.5 x 2 = 7

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Answer:

\frac{1}{12}X

Step-by-step explanation:

Let X is the number of hours Larry works a day

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As we know that, he has 6 students, so the fraction of his workday is spent with each student is:

\frac{1}{2}X : 6

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3 years ago
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Jan uses 6 grams of tea leaves to make 24 fluid ounces of tea. Last week she made 288 fluid ounces of tea. How many grams of tea
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Hello!

288 / 24 = 12

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4 0
3 years ago
Which equation could be used to find the length of the hypotenuse?
Komok [63]

Answer:

<h3>(base)² + (altitude)² = (hypotenuse) ²</h3>

Therefore,

2²+5² = c² will be matched.

7 0
3 years ago
A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for
Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

\implies h=\frac{1}{w^2}

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

= 2\times \frac{1}{w^2}(w+2w)

=\frac{6w}{w^2}

=\frac{6}{w}  

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}

=2w^2+4w^2+\frac{12}{w}

=6w^2+\frac{12}{w}

Differentiating with respect to w,

C'(w) = 12w -\frac{12}{w^2}

Again differentiating with respect to w,

C''(w) = 12 + \frac{24}{w^3}

For maxima or minima,

C'(w) = 0

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7 0
3 years ago
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NARA [144]
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To solve these equations, you can use anyone of these methods:
1) Graphing
2) Substitution
3) Elimination

The easiest way would be to graph them with a graphing calculator and find the point of intersection.
7 0
3 years ago
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