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SVEN [57.7K]
2 years ago
14

M is the midpoint of PQ. PM = 6x + 7 and MQ = 9x – 8, find the length of PQ.

Mathematics
1 answer:
koban [17]2 years ago
8 0

Answer:

The length of PQ is 64 units

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A bee flew 840 \text{ cm}840 cm840, space, c, m and landed on a flower to collect some pollen. Then the bee flew another 330 \te
alexdok [17]

Answer:

<em>The bee traveled 11.7 meters.</em>

Step-by-step explanation:

A bee flew 840 cm first to land on a flower to collect some pollen and then flew another 330 cm to get back to her hive.

For <u>finding the total distance traveled, we need to just add</u> 840 cm and 330 cm.

So, (840+330) cm = 1170 cm

We know that,  1 meter = 100 cm. That means, <u>for converting 'cm' into 'meter' , we need to divide by 100</u>.

Thus,  1170 cm= \frac{1170}{100} meter = 11.7 meter

So, the bee traveled 11.7 meters.

5 0
3 years ago
Frank's toy car is 19 centimeters long. Max's
jeka94

Answer:

Pertaining to the yielded interrogate, the retort is 6.30.

Step-by-step explanation:

As disseminated, the terms may equate to the proximate as identified:

-If an inch is equivalent to the numeral equivalence of 2.54, hence 5 inches (in) is in the accordance with the equivalence to 12.7 centimeters (cm).

Alas, the terms may equate as the following:

19 cm - 12.7 cm = x

Thus, as to resolute and evaluate the retort, with respect to your interrogate, is 6.30.

*Hope this helps.

8 0
3 years ago
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What is the solution to y=3/7x -1?
DedPeter [7]
Every point on the line 3/7x -1 is a solution

Unless there is another line provided...
6 0
3 years ago
What is the center of the circle shown below?<br><br>A. B<br><br>B. A<br><br>C. Y<br><br>D. AB
kirill115 [55]

If you look at the circle, center is B. It's located right in the center of the circle.

Answer

A. B

6 0
3 years ago
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Which expression represents the second partial sum for
NeTakaya

Answer:

S_{2} = 3\cdot \left(\frac{1}{2} \right)^{0} + 3\cdot \left(\frac{1}{2} \right)^{1}

Step-by-step explanation:

The first partial sum is:

S_{1} = 3\cdot \left(\frac{1}{2} \right)^{0}

The second partial sum is:

S_{2} = 3\cdot \left(\frac{1}{2} \right)^{0} + 3\cdot \left(\frac{1}{2} \right)^{1}

Which represents the option A.

6 0
3 years ago
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