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Anon25 [30]
3 years ago
12

Express 6 time the difference of 20 and 6 divide by 7 and simplify​

Mathematics
1 answer:
Stells [14]3 years ago
6 0

Answer:

Here's how to reduce a fraction: Break down both the numerator (top number) and denominator (bottom number) into their prime factors. Cross out any common factors. Multiply the remaining numbers to get the reduced numerator and denominator.

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If f(x) = 4x² – 3x + 8, then f(-2) =
Citrus2011 [14]

Answer: 30

Step-by-step explanation:

16+6+18

7 0
3 years ago
30 POINTS PLEASE HELP
user100 [1]

Answer:

If all other factors are controlled, and the only variable being changed is the new medication, then Byron can conclude that the new medication is effective at reducing coughing. This can be further tested by repeated experiments by peers. 

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
It is given that R=2q-5 and Q=3p+2. Find the numerical value of R when p=3​
saveliy_v [14]

Answer:

R = 17

Step-by-step explanation:

R = 2q - 5

Q = 3p + 2

Find the numerical value of R when p = 3

R = 2q - 5

R = 2(3p + 2) - 5

R = 6p + 4 - 5

R = 6p - 1

When p = 3

R = 6(3) - 1

R = 18 - 1

R = 17

4 0
3 years ago
Keith won a cash prize in an art competition. He gave his mother 2/5 of the money he won. Of the remainder, 1/4 was given to his
USPshnik [31]

Answer:

300 dollars

Step-by-step explanation:

Let the original amount = x

x - 2/5x  was what his mother's share looked.

5/5 x - 2/5 x

3/5x is what is left.

3/5 x - 1/4 * 3/5 x - 2/3x * 3/5 = his sister's share and his brothers

3/5x - 1/4*3/5 x - 2/3 * 3/5 = 15

3/5x * (1 - 1/4 - 2/3) = 15

3/5 x 5/60 = 15

15 / 300 * x = 15

1/20  x = 15

x = 15 * 20

x = 300

7 0
3 years ago
At most, how many unique roots will a third-degree polynomial function have?
beks73 [17]

The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.

In fact, if you use complex number, then a polynomial with degree n has exactly n roots.

So, in particular, a third-degree polynomial can have at most 3 roots.

In fact, in general, if the polynomial p(x) has solutions x_1,\ x_2,\ldots x_n, then you can factor it as

p(x) = (x-x_1)(x-x_2)\ldots (x-x_n)

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

p(x)=(x-x_1)(x-x_2)(x-x_3)(x-x_4)

But this is a fourth-degree polynomial.

7 0
3 years ago
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