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Anna11 [10]
2 years ago
7

10.

Mathematics
1 answer:
vodomira [7]2 years ago
3 0
<h3>Solution:</h3>
  • Given, side (a) = x+3
  • We know, surface area of a cube = 6a^2
  • Therefore, the surface area of the cube
<h3> </h3><h3>6(x + 3) ^{2}  \\  = 6( {x}^{2}  + 6x + 9) \\  = 6 {x}^{2}  + 36x + 54</h3><h3>Answer:</h3>

The answer is

{6x}^{2}  + 36x + 54

<h3>Hope it helps.</h3>

Sorry for delay

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Lara rides her skateboard 228 feet in 2 minutes what is her speed
Oliga [24]

Answer:

114 ft per minute

Step-by-step explanation:

To find the speed, take the distance and divide by the time

228 ft/ 2 minutes

114 ft per minute

7 0
3 years ago
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What is the slope of the line that passes through the points ( − 1 , − 7 ) (−1,−7) and ( 1 , − 13 ) (1,−13)? Write your answer i
Paraphin [41]

Answer:

y = -3x -10

Step-by-step explanation:

Slope-intercept formula: \frac{y_2-y_2}{x_2-x_1}

Find slope of  (−1, −7) and (1, -13)

\frac{y_2-y_2}{x_2-x_1}\\\\\\frac{-13-(-7)}{1-(-1)}\\\\\\frac{-6}{2}\\\\\-3

y = mx + b

y = -3x +b

y = -3x +b\\-7 = -3(-1) + b\\-7 = 3 +b\\-3   -3\\-10 = b

y = -3x -10

Hope this helps!

3 0
2 years ago
1=5 2=25 3=325 4=4325 6=?
Ipatiy [6.2K]

Answer:

6= 654325

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3 0
3 years ago
In a square with side length of 6, what is the distance between the center of the square and the center of the largest equilater
Vanyuwa [196]
Place the right angle at the origin. Short leg on x-axis.
The forth corner of the square is the point on the hypotenuse where the line y = x intersects. (Draw a diagram!)
In this case the hypotenuse is y = -4x/3 + 8
x = -4x/3 + 8
7x/3 = 8
7x = 24
x = 3.428571429
8 0
3 years ago
A model rocket is launched with an intitial upupward velocity of 202 ft/s. The rocket’s height h (in feet) after seconds is give
dsp73

Given that the height of a object thrown within a gravitational field is given as a quadratic equation in time, <em>t</em>, the time at which the object is at a specified height can be found by the quadratic formula

The values of, <em>t</em>, for which the height of the rocket is 82 feet are;

t = 12.21 seconds or t = 0.42 seconds

Question: <em>Parts of the question that appear missing but can be found online are (i) To find the values of the time, t, when the rocket's height is 82 feet and round answers to the nearest hundredth</em>

The known parameters of the rocket are;

The initial upward velocity of the rocket, v = 202 ft./s

The given function representing the height, <em>h</em>, (in feet) after <em>t</em> seconds is presented as follows;

H = 202·t - 16·t²

The unknown;

The time for which the height of the rocket is 82 feet

Method;

Substitute H = 82 feet in the height function equation and solve for <em>t</em> as follows;

When H = 82, we get;

82 = 202·t - 16·t²

Therefore;

16·t² - 202·t + 82 = 0

Dividing the above equation by <em>2</em> gives;

(16·t² - 202·t + 82)/2 = 0/2

8·t² - 101·t + 41 = 0

By using the quadratic formula, we get;

\mathbf{t = \dfrac{101 \pm \sqrt{(-101)^2 - 4 \times 8 \times 41} }{2 \times 8}  =  \dfrac{101 \pm \sqrt{8889} }{16}}

Therefore, the values of <em>t</em> given by rounding off to the nearest hundredth are;

t = 12.21 or t = 0.42

The values of the time, <em>t</em>, at which the height of the rocket is 82 feet are t = 12.21 seconds or t = 0.42 seconds

Learn more about equation models of height as a function of time here;

brainly.com/question/84352

7 0
3 years ago
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