Hi there!


We can evaluate using the power rule and trig rules:



Therefore:
![\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B12%7D_%7B2%7D%20%7Bx-sin%28x%29%7D%20%5C%2C%20dx%20%3D%20%5B%5Cfrac%7B1%7D%7B2%7Dx%5E%7B2%7D%2Bcos%28x%29%5D_%7B2%7D%5E%7B12%7D)
Evaluate:

Answer:
y=-x-4
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given
Negative integer J
Required
Represent as an inequality of its inverse
The question didn't state if it's additive inverse or multiplicative inverse;
<em>Since the question has to do with negation, I'll assume it's an additive inverse</em>
<em></em>
The inverse of -J is +J
To represent as an inequality (less than or equal), we have:

Solving further, it gives

Answer:
Choice B is correct
Step-by-step explanation:
The given radical division can be expressed in the following form;

Using the properties of radical division, the expression can be expressed in the following form;

Simplifying further yields;

Choice B is thus the correct alternative