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3 years ago

In which number is the value of the 5 ten times greater than the value of the 5 in 654,321? 658,321 536,401 65,892 58

Mathematics

1 answer:

krok68 [10]3 years ago

5 0

Answer:

536,401

Step-by-step explanation:

the 5 is in the ten thousands column in 654,321. you have to times the number by ten to see what column it would be in, 6,543,210. The 5 is now in the hundred thousands column. The only number there with the 5 in in the hundred thousands column is 536,401.

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Two sides of a triangle are 12 and 18 cm. Complete the inequality to show the possible lengths of the third side.

musickatia [10]

Let a = 12 and b = 18 be the two given sides

Let c be the unknown third side

Due a modified form of the triangle inequality theorem, we know that,

b-a < c < b+a

18-12 < c < 18+12

6 < c < 30 which is the final answer

This says c is between 6 and 30, but cannot equal either endpoint.

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3 years ago

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3 years ago

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2 years ago

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A car is traveling at a speed of miles per hour. What is the car's speed in kilometers per hour? How many kilometers will the ca

mihalych1998 [28]

Complete Question:

As you may have intentionally forgotten to mention the important data elements in your question like at what rate a car is travelling and number of hours car will travel in required number of miles etc. After a little research it seems I have found the complete question you were supposed to write. Hence, I am answering based on this complete question, but anyways, it would certainly improve your concept. Here is the complete question:

A car is traveling at a rate of 60 kilometers per hour. What is the car's rate in miles per hour? How many miles will the car travel in 4 hours? In your computations, assume that 1 mile is equal to 1.6 kilometers. Do not round your answers.

Answer:

The car will travel 37.5 miles in one hour.

The car travel 150 miles in 4 hours.

Fetching data from Question:

The rate at which car is traveling: 60 kilometers per hour

one mile = 1.6 km

a) How many miles a car will travel in one hour?

b) How many miles will the car travel in 4 hours?

Calculation:

a) How many miles a car will travel in one hour?

As one mile is equal to 1.6 km.

The rate at which car is traveling: 60 kilometers per hour

So, just divide 60 with 1.6 to get in miles

i.e. 60/1.6 = 37.5 miles per hour

So, the car will travel 37.5 miles in one hour.

b) How many miles will the car travel in 4 hours?

As the car will travel 4 hours.

And car travels 37.5 miles in one hour

So, just multiply the number of hours i.e. 4 with the miles in one hour (speed) i.e. 37.5 to calculate the distance in 4 hours. So,

The distance = speed × time

= 37.5 × 4

= 150 miles

So, the car travel 150 miles in 4 hours.

Keywords: distance, speed, kilometers, miles

learn more about distance travel and speed from brainly.com/question/12580265

#learnwithBrainly

4 0

3 years ago

Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a

Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = $5*sin(\frac{2*\pi*t}{15} )+6$

When Jamie is 9 meters above the ground and rising we have

9 = $5*sin(\frac{2*\pi*t}{15} )+6$ or 3/5 = $sin(\frac{2*\pi*t}{15} )$ = 0.6

which gives sin⁻¹(0.6) = 0.643 = $\frac{2*\pi*t}{15}$

from where t = 1.536 s

Therefore Jamie is gaining altitude at

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ 1.676 m/s.

(b) Jamie is rising most rapidly when the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

$\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15})$ =0, π, 2π

Therefore $-sin(\frac{2\pi t}{15} )$ = 0 whereby t = 0 or

$\frac{2\pi t}{15}$ = π and t = 7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ - 2/3π m/s which is decreasing

so we try at t = 15 s and we have $\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pi$ m/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

7 0

3 years ago